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vaieri [72.5K]
2 years ago
4

Consider two identical conducting spheres whose surfaces are separated by a small distance. One sphere is given a large net posi

tive charge, while the other is given a small net positive charge. It is found that the force between them is attractive even though both spheres have net charges of the same sign. Explain how this is possible.
Physics
1 answer:
Andrews [41]2 years ago
6 0

Answer

The positive charge on one sphere will attract an electron on another sphere. And since the positive charge on other sphere is small, so the part of the sphere which is near the first sphere will be distributed with the electron.

We know the electric force is larger as the distance decrease.

Since the electron part of the 2nd sphere near the first sphere more than the positive part.

So the net force is attracting.

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Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long. How long is the ot
s344n2d4d5 [400]

Answer:

The length of the longer pipe is L = 2.30 m

Explanation:

Given that:

Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long.

How long is the other pipe?

From above;

The formula for the frequency of open ended pipes can be expressed as:

f = \dfrac{nv}{2L}

where n = 1 ( since half wavelength exist between those two pipes)

v = 343 m/s  and L = 2.08 m

Thus, the shorter pipe produces a frequency of :

f = \dfrac{1*343}{2*2.08}

f = \dfrac{343}{4.16}

f =82.45 \ Hz

Also; we know that the beat frequency was given as 8.0 Hz

Then,

The lower frequency of the longer pipe = ( 82.45 - 8.0 )Hz

The lower frequency of the longer pipe = 74.45 Hz

Finally;

From the above equation; make Length L the subject of the formula. Then,

The length of the longer pipe is L = \dfrac{nv}{2f}

The length of the longer pipe is L = \dfrac{1*343}{2*74.45}

The length of the longer pipe is L = \dfrac{343}{148.9}

The length of the longer pipe is L = 2.30 m

6 0
2 years ago
Read the lab procedure for a controlled experiment that looks at the effect of heat on the circumference of bicycle tires.
solniwko [45]

Explanation :

To start any lab work initially, we have to know the theory behind the experiment. After then the experiment should be started. At the end, the readings must be taken carefully and some conclusion can be drawn.

Some of the steps are given :

Step 1: Pump up six identical bike tires to the recommended air pressure.

Step 2: Place three tires under heat lamps, and keep the other three tires at room temperature.

Step 3: After four hours, measure the circumference of each tire.

Step 4: Record your results in the table.

The fifth step should be :

Step 5: Write the result or conclusion that shows what you have done during the entire experiment.

4 0
2 years ago
Read 2 more answers
Study the free body diagram above. Which scenario below can best be described with this free body diagram? A. a cup is at rest o
vekshin1

Answer: D

Explanation:

5 0
2 years ago
Assuming the same current is running through two separate coils, why is it easier to thrust a magnet into a wire coil with one l
s2008m [1.1K]
The magnetic field strength in a coil is directly proportional to the number of turns, or loops, in the coil.
Therefore, when there are four loops instead of one, the magnetic field strength has increased four times, making it harder to push the magnet in.
6 0
2 years ago
Read 2 more answers
(a) A 15.0 kg block is released from rest at point A in the figure below. The track is frictionless except for the portion betwe
castortr0y [4]

Answer:

(a) coefficient of friction = 0.451

This was calculated by the application of energy conservation principle (the total sum of energy in a closed system is conserved)

(b) No, it comes to a stop 5.35m short of point B. This is so because the spring on expanding only does a work of 43 J on the block which is not enough to meet up the workdone of 398 J against friction.

Explanation:

The detailed step by step solution to this problems can be found in the attachment below. The solution for part (a) was divided into two: the motion of the body from point A to point B and from point B to point C. The total energy in the system is gotten from the initial gravitational potential energy. This energy becomes transformed into the work done against friction and the work done in compression the spring. A work of 398J was done in overcoming friction over a distance of 6.00m. The energy used in doing so is lost as friction is not a conservative force. This leaves only 43J of energy which compresses the spring. On expansion the spring does a work of 43J back on the block is only enough to push it over a distance of 0.65m stopping short of 5.35m from point B.

Thank you for reading and I hope this is helpful to you.

4 0
2 years ago
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