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2 years ago

Read the lab procedure for a controlled experiment that looks at the effect of heat on the circumference of bicycle tires.

Physics

2 answers:

fgiga [73]2 years ago

8 0

Answer:

Step 5: Draw conclusions and write the final result

Explanation:

In controlled experiment, after all the steps of the experiment, the observations are written in the table.

In the given lab procedure for the effect of heat on the circumference of bicycle tires. In step 5, the recorded result must be analysed and conclusion must be drawn and final result must be written.

solniwko [45]2 years ago

4 0

Explanation :

To start any lab work initially, we have to know the theory behind the experiment. After then the experiment should be started. At the end, the readings must be taken carefully and some conclusion can be drawn.

Some of the steps are given :

Step 1: Pump up six identical bike tires to the recommended air pressure.

Step 2: Place three tires under heat lamps, and keep the other three tires at room temperature.

Step 3: After four hours, measure the circumference of each tire.

Step 4: Record your results in the table.

The fifth step should be :

Step 5: Write the result or conclusion that shows what you have done during the entire experiment.

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Valentin [98]

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3 years ago

Read 2 more answers

A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long, what is the

egoroff_w [7]

The acceleration of the jet is $28.1 m/s^2$

Explanation:

Since the motion of the jet is a uniformly accelerated motion, we can use the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the jet in this problem, we have

u = 0

v = 75 m/s

s = 100 m

Solving for a, we find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{75^2-0}{2(100)}=28.1 m/s^2$

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2 years ago

1. Suppose a tank filled with water has a liquid column with a height of 10 meters. If the area is 2 square meters (m²), what's

Anit [1.1K]

Answers:

1. Firstly, we have to define that Pressure $P$ is Force applied $F$ per unit area $A$ . It is mathematically expressed as follows:

$P=\frac{F}{A}$ (1)

The unit of P is Pascal (Pa) which is equivalent to $\frac{kg}{ms^{2}}$ and also equivalent to $\frac{N}{m^{2} }$

There is also another expression of the Pressure in which it is dependent on the density $d$ of the liquid, the height $h$ of the container and the gravity force $g$ :

$P=d*h*g$ (2)

In this problem the liquid is water, and its known density is approximately:

$d=1000kg/m^{3}$

So, we have to substitute the values in equation (2) to obtain the pressure (Being careful with the units):

$P=1000\frac{kg}{m^{3}}*10m*9.8\frac{m}{s^{2}}$

$P=98000Pa$

Then, we have to substitute this value in equation (1) and clear $F$ :

$F=P*A$

Finally:

$F=196000N$

2. For this problem, we will use equation (1) to find the Pressure. We already know the area $A$ and the force exerted by water in the container $F$ :

$P=\frac{F}{A}=\frac{900N}{3m^{2}}$

$P=300Pa$

3. In this case, equation (2) is the perfect way to find the hydrostatic pressure at any point at the bottom of the tank (be careful with the units):

$P=d*h*g$

$P=1000\frac{kg}{m^{3}}*7.5m*9.8\frac{m}{s^{2}}$

$P=73500Pa$

4. In this case, it's important to know that in fluids (in this case the water) the higher the fluid is, the lower the pressure. Then, if $P_{1}$ and $P_{2}$ are the respective pressures at the heights $h_{1}$ and $h_{2}$ , and knowing that the water density and the gravity force in this case are constants, we can use the following expression to solve this problem: