Question

URGENT!! A​ solid-gold jewelry box was found in the underwater palace of Cleopatra just off the shore of Treasure City. The length of the rectangular box is 21 centimeters less than triple the width. The perimeter of the box is 230 centimeters. Find the length and width of​ Cleopatra's solid-gold jewelry bo

Answer 1

Answer:

Width = 34 cm

Length = 81 cm

Step-by-step explanation:

Let length be l and width be w

Let perimeter be p or p = 2(l+w)

The length of the rectangular box is 21 centimeters less than triple the width:

This means

l = 3w - 21

Also, perimeter is 230, so

2(l+w) = 230

or

l+w = 115

Putting equation 1 in this equation, we get:

l+w=115

(3w - 21)+w=115

Solving:

$(3w - 21)+w=115\\4w=136\\w=34$

To find length:

l = 3w - 21

l = 3(34) - 21

l = 81

Hence

Width = 34 cm

Length = 81 cm