Since the Σ( of all colors )= 100%, OR 1, then:
a) P(GREEN ∪ BLUEU) = P(G) + P(BL) = 8%+6% = 14% or 0.14
Since we have to choose ONE candy and only ONE candy at random, then tey are mutually exclusive: No. Choosing a green and blue M&M is possible
b) P(YELLOW ∪ RED) = P(Y) + P(R) = 18%+18% = 36% or 0.36
SAME ANSWER AS BEFORE: mutually exclusive
c) P(NOT PURPLE), Let's calculate 1st, the probability of having a PURPLE:
P(PURPLE) = 21% or 0.21
And the Probability of NOT having a PURPLE is 1-0.21 = 0.79
the final price of the wind chime is $29.925 .
<u>Step-by-step explanation:</u>
Here we have , A home improvement store sold wind chimes for $30 each. A customer signed up for a free membership card and received a 5% discount off the price. Sales tax of 5% was applied after the discount. We need to find What was the final price of the wind chime . Let's find out:
Initially we have , 5% discount in $30 i.e.
⇒ (30(5))/100
⇒ (150)/100
⇒ $1.5 , So now price becomes $30 - $1.5 = $28.5 . At this amount there's 5% tax i.e.
⇒ (28.5(5))/100
⇒ (142.5)/100
⇒ $1.425
So now price becomes $28.5 + $1.425 = $29.925 . Therefore , the final price of the wind chime is $29.925 .
The data has been properly arranged in tabular form and is shown below in the image.
First we need to find the mean and median of scores of both students.
1) For Amo:
Mean =

Median = Middle Value when data is arranged in ascending order = 90
2) For Javier:
Mean =

Median = Middle Value when data is arranged in ascending order = 92
For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.
Original price of the item = $14.95
Price after discount = $13.79
Discount offered = original price - price after discount = 14.95- 13.79 = $1.16
Now let us find the percentage of discount offered.
Percentage discount is given by the formula:

Where MP= Marked price= original price
SP= selling price= price after discount

Percentage discount = 7.759 %
Answer:
Translate K to N and rotate about K until HK lies on the line containing LN.
Step-by-step explanation:
Hope this helps bb's!!
Lots of love and peace your way!! <3