Question

Two computers just scanned for viruses at the same time. Computer A runs a virus scan every 2.75 days. Computer B runs a virus scan every 3.5 days. How long will it be until both computers run a virus scan at the same time again?

Answer 1

Answer:

9.625 days

Step-by-step explanation:

That would be 2.75 * 3.5 = 9.625 days.

Answer 2

Answer : The time taken when both computers run a virus scan at the same time again is, 1.54 days

Step-by-step explanation :

Let the time taken by computer for virus scan be, 'x' days

As we are given that Computer A runs a virus scan every 2.75 days and Computer B runs a virus scan every 3.5 days. The work is same.

Amount of work done by computer A:

Amount of work done in 1 day = $\frac{1}{2.75}$

Amount of work done in 'x' day = $\frac{x}{2.75}$

Amount of work done by computer B:

Amount of work done in 1 day = $\frac{1}{3.5}$

Amount of work done in 'x' day = $\frac{x}{3.5}$

As the work is same. That means, the amount of work done is, 1.

Now we have to determine the time taken when both computers run a virus scan at the same time again.

$\frac{x}{2.75}+\frac{x}{3.5}=1$

By solving the term 'x', we get:

$\frac{(3.5+2.75)x}{2.75\times 3.5}=1$

$\frac{(6.25)x}{9.625}=1$

$x=1.54days$

Thus, the time taken when both computers run a virus scan at the same time again is, 1.54 days