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Stolb23 [73]
2 years ago
5

today Ned got a new credit card, and he made a purchase of $1100. the card offers an introductory APR of 0% for the first 3 mont

hs and a standard APR of 34.3% thereafter. if the card compounds interest monthly, how much money will the introductory APR save Ned in interest over the first 3 months? (Assume that ned will make no payments or additional purchases during the first 3 months, and ignore any possible late payment fees)... a) $442.65 b)$1197.05 c)$97.05 d)$1542.65
Mathematics
2 answers:
White raven [17]2 years ago
8 0
A= P(1+r/n)^nt

P<span> =</span> principal amount (the initial amount you borrow or deposit)

r  = annual rate of interest (as a decimal)

t<span>  = </span>number of years the amount is deposited or borrowed for.

A<span> =</span><span> amount of money accumulated after n years, including interest.</span>

n  =  number of times the interest is compounded per year

A= 1100(1+0.343/12)^12/4

A = 1197.04

Amount saved = 1197.04 - 1100 = $ 97.04

Evgen [1.6K]2 years ago
8 0

Answer:

Apex answer is 97.05.

Step-by-step explanation:


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(10 2/3)/(11/20)

(32/3)/(11/20)

(32/3)*(20/11)

640/33

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2 years ago
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2 years ago
Mary spent $45 at the mall. She bought lunch for $9. She bought 3 shirts at
oee [108]

Answer:

x = 12

Step-by-step explanation:

If Mary spent $45 altogether,

then she bought lunch for $9

so our equation now is

$45 = $9 + 3x

It is 3x because he bought 3 shirts and we used x because we didnt

now how much the price of those shirts were

$45 = $9 +3x

$45 - $9 = 3x

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$36 = 3x

$36 / 3 = 12

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Please mark this answer as the brainliest

4 0
2 years ago
PLEASE HELP TO SOLVE QUESTION with full process c) Mr. Thapa bought a motorbike for Rs 1,25,000 and fixed its price 20 % above t
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Step-by-step explanation:

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10% discount = 150000*10% = 15000

SP after 10% discount

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8 0
2 years ago
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A circle has diameter of 11cm
dlinn [17]

Since length of diagonal (  Diagonal= 9.9cm ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.

<u>Step-by-step explanation:</u>

Here we have , A circle has diameter of 11 cm  A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:

We know the concept that for any square to fit inside the circle without touching the edge of circle  , diagonal of square must be less than diameter of circle  . Let's find out length of diagonal by using Pythagoras Theorem :

Hypotenuse ^2 = Perpendicular^2+Base^2

For a square , Perpendicular = base = side

⇒ Diagonal^2 = 2(side)^2

⇒ Diagonal= \sqrt{2}(side)

⇒ Diagonal= \sqrt{2}(7)

⇒ Diagonal= 9.9cm

Since length of diagonal (  Diagonal= 9.9cm ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.

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2 years ago
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