Answer:

Step-by-step explanation:
given is the Differential equation in I order linear as

Take Laplace on both sides
![L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}](https://tex.z-dn.net/?f=L%28y%27%29%20%2B4L%28y%29%20%3D%2048L%28t%29%5C%5CsY%28s%29-y%280%29%20%2B4Y%28s%29%20%3D%2048%20%2A%5Cfrac%7B1%7D%7Bs%5E2%7D%20%5C%5CY%28s%29%20%5Bs%2B4%5D%3D%5Cfrac%7B48%7D%7Bs%5E2%7D%2B9%5C%5CY%28s%29%20%3D%20%5Cfrac%7B1%7D%7Bs%5E2%28s%2B4%29%7D%2B%5Cfrac%7B9%7D%7Bs%2B4%7D)
Now if we take inverse we get y(t) the solution
Thus the algebraic equation would be
The function for conversions from Fahrenheit to Celsius is:
Celsius = (Fahrenheit - 32) x 5/9
C(76.1) = (76.1 - 32) x 5/9
= (44.1) x 5/9
= 24.5
Therefore, 76.1 degrees Fahrenheit = 24.5 degrees Celsius.
By Green's theorem, the integral of
along
is

which is 6 times the area of
, the region with
as its boundary.
We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle
and radius
, the area
of the sector is proportional to the circle's overall area according to

so that the value of the integral is
