Answer:
a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)
=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363
hence probability that it actually contains explosives given identified as containing explosives)
=(10/(4*106))*0.95/0.005002363=0.000475
b)
let probability of correctly identifying a bag without explosives be a
hence a =0.99999763 ~ 99.999763%
c)
No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,
Answer:
72 yrs old.
Step-by-step explanation:
The combined age
D+O=96
The owner is 3 times older than dog
O=3D
D+3D=96
4D = 96
D= 24
Now substitute the value of D in O=3D
O=3.24= 72
The owner is 72 years old.
Step-by-step explanation:
×=100
1. Divded 35 by 14 and u get 0.4
2
Divided 40 by 0.4 and u get 100
7 batches of cookies 14 x 7=98 whereas sandy needs 12 x 8=96 ,so 7 batches would be perfect
Answer:
oops sorry accidental click i don't know how to get out sorry for letting you down
Step-by-step explanation:
