Question

A block of copper of unknown mass has an initial temperature of 65.4 degress celcuis. THe copper is immersed in a beaker containing 95.7 g water at 22.7 degress celcius. When the two substances reach thermal equilibrium, the final temperature is 24.2 degrees celcius. What is the mass of the copper block?

Answer 1

Answer:

The answer to your question is: m = 37.88 g

Explanation:

Data

                  Copper                   Water

mass               ?                          95.7 g

Cp               0.092 cal/g°C        1 cal/g°C

T1                65.4°C                     22.7°C

T2                24.2°C                    24.2°C

Formula

                   Q copper = Q water

Q = mCp(T2 - T1)

                  - m(0.092)(24.2 - 65.4) = 95.7(1)(24.2 - 22.7)

                   m = 95.7(1)(24.2 - 22.7) /- (0.92)(24.2 - 65.4)

                   m = 143.55 / 3.79

                   m = 37.88 g