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Nonamiya [84]
2 years ago
3

The data represents the number of players who turned out for 9 different youth soccer teams. {32, 28, 22, 28, 16, 12, 20, 22, 20

} What is the five-number summary? Minimum = 12Q1= 16Median = 19.5Q3= 24Maximum = 32 Minimum = 12Q1= 16Median = 22Q3= 26.5Maximum = 32 Minimum = 12Q1= 18Median = 22Q3= 28Maximum = 32 Minimum = 12Q1= 18.5Median = 20Q3= 26Maximum = 32
Mathematics
1 answer:
kirill [66]2 years ago
8 0

Answer:

See below in bold.

Step-by-step explanation:

32, 28, 22, 28, 16, 12, 20, 22, 20

Rearrange in ascending order:

12, 16, 20, 20, 22, 22, 28, 28, 32  So:

Minimum = 12.

Median = 22      ( the median is the middle number).

Maximum = 32.

Q1  =   18      (This is the Lower Quartile:  18 is the mean of 16 and 20).

Q3 = 28      (The Upper Quartile)

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A matrix contains 60 elements. Which of the following cannot equal the number of rows of the matrix?
avanturin [10]

<span>Given:

Matrix = 60 elements</span>

 

<span>To solve this, we need to take into account that each row must contain the same number of elements. So, we need to find which of the options do not divide evenly into 60 (the options are 30, 60, 10, and 18).

So we check each of the choices to see if 1 of them divides evenly with 60.

60 / 60 = 1 (divides evenly)</span>

60 / 30 = 2 (divides evenly)

<span>60 / 10 = 6 (divides evenly)
</span>60 / 18 = 3.3.3333333333333333333333333333333 (does not divide evenly)

Therefore, 18 cannot equal the number of rows of the matrix.

6 0
2 years ago
An equilateral triangle has a semiperimeter of 6 meters.
guapka [62]

Answer:

7

Step-by-step explanation:

An equilateral triangle has a semiperimeter of 6 meters.

Heron’s formula: Area = StartRoot s (s minus a) (s minus b) (s minus c) EndRoot

An equilateral triangle has a semiperimeter of 6 meters. What is the area of the triangle? Round to the nearest square meter.

2 square meters

7 square meters

20 square meters

78 square meters

7 0
2 years ago
Read 2 more answers
A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3
butalik [34]

Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

(x - 3)² + (y - 4)² = 9

The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

(x - 3)² + (5 - 4)² = 9

(x - 3)² + 1 = 9

(x - 3)² = 8

(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

8 0
2 years ago
The exponential distribution can be used to solve Poisson-type problems in which the intervals are not time. The Air Travel Cons
frutty [35]

Answer:

a) P(X \ge 490) = 0.628

b) P(X \leq 190) = 0.165

Step-by-step explanation:

a) This is an exponential distribution question since it is a poisson type problem

Mean rate is 0.95 per 1000 passengers

Mean rate, \lambda = 0.95/1000

\lambda = 0.00095 per passenger

Probability that at least 490 passengers will have their baggage handled properly before the next mishandling occurs :

P(X \ge x) = e^{- \lambda x}

P(X \ge 490) = e^{-490 * 0.00095}

P(X \ge 490) = e^{-0.4655}\\P(X \ge 490) = 0.628

b)  Probability that the number will be fewer than 200 passengers

P(X \leq 190) = 1 - P(X \geq 190)\\P(X \leq 190) = 1 - e^{-190 \lambda} \\P(X \leq 190) = 1 - e^{-190 *0.00095}

P(X \leq 190) = 1 - 0.835\\P(X \leq 190) = 0.165

8 0
2 years ago
You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th
finlep [7]
The <u>correct answer</u> is:

9.2 ft.

Explanation:

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d=\frac{|Am+Bn+C|}{\sqrt{A^2+B^2}}

We first need to write our equation in the form Ax+By+C=0.
y=(-6/7)x+7

First we will add 6/7x to each side:
y+6/7x=(-6/7x)+7+(6/7x)
y+6/7x=7

Now we will subtract 7 from each side:
y+6/7x-7=7-7
y+6/7x-7=0

It will be easier to work with this equation if we do not have fractions.  We can accomplish this by multiplying everything by the denominator of the fraction, 7:
y(7)+(6/7x)(7)-7(7)=0
7y+(42/7)x-49=0
7y+6x-49=0

Now we rearrange the terms to the x term is in front:
6x+7y-49=0

This is in the form Ax+By+C=0, where A=6, B=7 and C=-49.

Substituting these into our formula above along with our coordinates from our point (m,n)=(6, 14) we have:
d=\frac{|Am+Bn+C|}{\sqrt{A^2+B^2}}&#10;\\&#10;\\d=\frac{|6(6)+7(14)-49|}{\sqrt{6^2+7^2}}&#10;\\&#10;\\d=\frac{|36+98-49|}{\sqrt{36+49}}&#10;\\&#10;\\d=\frac{|85|}{\sqrt{85}}=\frac{85}{\sqrt{85}}=9.2&#10;
7 0
2 years ago
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