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jeka94
1 year ago
9

Erica wants to replace her old washing machine with a new one. In order to get the maximum value for her money, she plans to spe

nd substantial time and effort in gathering information and making product comparisons before making the actual purchase. In this instance, Erica is planning to buy a(n) ________ product. Group of answer choicesA) convenienceB) unsoughtC) specialtyD) shoppingE) exclusive
Business
1 answer:
Makovka662 [10]1 year ago
3 0

Answer:

D. shopping

Explanation:

You might be interested in
Adirondack Marketing Inc. manufactures two products, A and B. Presently, the company uses a single plantwide factory overhead ra
AnnZ [28]

Answer:

a.$15.07 per unit

Explanation:

Using a single plantwide overhead rate based on direct labor hours each product is assigned $15.07 of overhead per unit.

Plantwide overhead rate = Total Budgeted Overhead/ Total Budgeted Direct Labor Hours

Plantwide overhead rate =  $320,900/ 21,300= $ 15.065= $ 15.07

                     Overhead    Total Direct Labor Hours DLH per Product A B

Painting Dept.            $255,200           10,100                 3       11

Finishing Dept.         65,700                  11,200                     6       7

Totals                       $320,900              21,300                   9      1

6 0
1 year ago
Diogo has a utility function,U(q1, q2) = q1 0.8 q2 0.2,where q1 is chocolate candy and q2 is slices of pie. If the price of slic
guapka [62]

Answer:

(0.5 \times 8q_2)+q_2=100\\\\5q_2=100\\\\q_2=20

since q_2 = 20

q_1 = 8*20\\\\q_1=160

Explanation:

U(q₁ q₂)

q_1^{0.8}q_2^{0.2}\\\\P_1= \$0.5 \ P_2=\$1 \ Y=100

Budget law can be given by

P_1q_1+P_2q_2=Y\\\\0.5q_1+q_2=100

Lagrangian function can be given by

L=q_1^{0.8}q_2^{0.2}+ \lambda (100-0.5q_1-q_2)

First order condition csn be given by

\frac{dL}{dq} =0.8q_1^{-0.2}q_2^{0.2}-0.5 \lambda=0\\\\0.5 \lambda=0.8q_1^{-0.2}q_2^{0.2}---(i)

\frac{dL}{dq} =0.2q_1^{0.8}q_2^{-0.8}- \lambda=0\\\\ \lambda=0.2q_1^{0.8}q_2^{-0.8}---(ii)

\frac{dL}{d \lambda} =100-0.5q_1-q_2=0\\\\0.5q_1+q_2=100---(iii)

From eqn (i) and eqn (ii) we have

\frac{0.5 \lambda}{\lambda} =\frac{0.8q_1^{-0.2}q_2^{0.2}}{0.2q_1^{0.8}q_2^{-0.8}} \\\\0.5=\frac{4q_2}{q_1}\\\\q_1=8q_2}

Putting q_1=8q_2 in euqtion (iii) we have

(0.5 \times 8q_2)+q_2=100\\\\5q_2=100\\\\q_2=20

since q_2 = 20

q_1 = 8*20\\\\q_1=160

3 0
1 year ago
Kawasaki Company incurred the following unit costs in manufacturing digital cameras: Direct Materials $14 Indirect Materials (va
Shtirlitz [24]

Answer:

Unitary variable cost= $42

Explanation:

Giving the following information:

Direct Materials $14

Indirect Materials (variable) $4

Direct Labor $8

Indirect Labor (variable) $6

Other Variable Factory Overhead $10

During the period, the company produced and sold 1,000 units.

Under the variable cost method, the product cost is calculated using direct material, direct labor, and variable overhead:

Unitary variable cost= 14 + 8 + (4 + 6 + 10)= $42

0 0
1 year ago
Journey's the shoe store has a cost of goods sold of $22.00 on classic Converse Chuck Taylor sneakers. The corporate office mand
velikii [3]

Answer:

Explanation:

Firs, find the markup amount in dollars;

Markup amount = Cost * markup rate

Cost = $22

markup rate = 30% or 0.30 as a decimal

Markup amount = 0.30*22 = $6.6

Next, find the retail price using the markup amount calculated above;

Retail Price = Markup amount + cost

Retail price = $6.6 +$22

= $28.6

Therefore, the sneakers retail price is $28.6

4 0
1 year ago
Suppose you are running a carnival. You are selling hamburgers and sodas. A hamburger is $1.75 and a soda is .75. You expect to
Sunny_sXe [5.5K]

Answer:

<em>Hamburgers = 27</em>

<em>Sodas = 93</em>

Explanation:

Let        x = Hamburgers

             y= Sodas

Now form a system of equation aX + bY = C

where

a= 1.75 = coefficient of variable X

b= 0.75 = coefficient of variable Y

C= 117.50

Put these values in above equation

           1.75x + 0.75y = 117.50 . . . . . (1)

Since I sold total of 120 hamburgers and sodas, we can write

            x + y = 120  . . . . . (2)

or          y = 120 - x          ....... put this value in eq.1

           1.75x + 0.75( 120 - x ) = 117.50

           1.75x + 90 - 0.75x = 117.50

            90 + x = 117.50

             x = 117.50 - 90

             x = 27     .......... put this in equation 2

     

          x + y = 120

          27 + y = 120

          y = 120 - 27

           y = 93

3 0
1 year ago
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