Answer:
Step-by-step explanation: Uhh I have no idea how I got this right because I guessed but
small: 3-5 pounds 0.25+1.2+2.7
Medium: 5-8 pounds 0.25+0.25+1.2+1.2+1.2+1.2
Large 8-10 pounds 0.25+1.2+1.2+1.2+2.7+2.7
Hope I helped this is my first time answering a question have a good day everyone
There is no option of the box plots, so I have created a version that would represent this data.
To make the box plot you will need the lower extreme, lower quartile, median, upper quartile, and upper extreme.
Please see the attached picture.
For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.
For the given case we have following values and their probabilities:
0 : 0.1
2 : x
3 : y
So the expected value will be = 0(0.1) + 2(x) + 3(y)
Expected value is given to be 2.05. So we can write the equation as:
2x + 3y = 2.05 (Equation 1)
Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:
0.1 + x + y = 1
x + y = 0.9 (Equation 2)
From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:
2(0.9 - y) + 3y = 2.05
1.8 - 2y + 3y = 2.05
1.8 + y = 2.05
y = 0.25
Using the value of y in equation 2 we get value of x to be 0.65
Therefore we can conclude that:
The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25
It will be a kid getting hit in the leg by the kids in the lunch table so it will be 4
