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Ede4ka [16]
2 years ago
11

According to the rational root theorem, which number is a potential root of f(x) = 9x8 9x6 – 12x 7?

Mathematics
2 answers:
yaroslaw [1]2 years ago
7 0

The options of the problem are

A. 0\ B. \frac{1}{7}\ C. 2\ D. \frac{7}{3}

we have

9x^{8} +9x^{6} - 12x +7

we know that

<u>The Rational Root Theorem </u>states that when a root 'x' is written as a fraction in lowest terms

 x=\frac{p}{q} 

p is an integer factor of <u>the constant term</u>, and q is an integer factor of <u>the coefficient of the first monomial</u>.

So

in this problem

the constant term is equal to 7

and the first monomial is equal to 9x^{8} -----> coefficient is 9

therefore

<u>the answer is the option </u>

D. \frac{7}{3}

Alchen [17]2 years ago
5 0
Thank you for posting your math problem here in brainly. <span>According to the rational root theorem, the potential root of f(x) = 9x8 9x6 – 12x 7 are </span><span>±1, ±2, ±4,</span> <span>±<span>13</span>, ±<span>23</span>, ±<span>43</span>, </span> <span>±<span>19</span>, ±<span>29</span>, ±<span>49. I hope my answer helps. </span></span>
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(x + b/2a)² = -c/a + (b/2a)² =  -c / a + b²/4a² = (-4ac+ b²)/4a²

(x + b/2a)² =  (-4ac+ b²)/4a²

  • square root both sides

√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}

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x + b/2a  =  √( b²-4ac) / 2a

  • subtract b/2a from both sides

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7 0
2 years ago
vegetable ghee is stored in the cylindrical vessel of internal radius 1.4m height 1.5m. if it is transferred into the rectangula
irina1246 [14]

Answer:

<em>5,598 cans are required to empty the vessel</em>

Step-by-step explanation:

The volume of a cylinder of radius r and height h is:

V = \pi r^2h

The volume of a box of dimensions X, Y, and Z is:

V=X.Y.Z

A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:

V_1 = \pi 1.4^2*1.5

V_1=9.236\ m^3

Converting to cubic cm:

V_1=9.236*1,000,000\ cm^3

V_1=9,236,282\ cm^3

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V_2=33*10*5=1,650\ cm^3

V_2=1,650\ cm^3

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V_1/V_2=9,236,282/1,650 = 5,598

5,598 cans are required to empty the vessel

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2 years ago
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Answer:

a) 1+2+3+4+...+396+397+398+399=79800

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We know that a summation formula for the first n natural numbers:

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\frac{39·(39+1)}{2}=S/2

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2+4+6+8+...+72+74+76+78=1560

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2 years ago
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