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Dmitriy789 [7]
2 years ago
13

Megan consumed 3.5 gallons of water in one day. How many milliliters are equal to 3.5 gallons, if 1 liter = 1,000 milliliters an

d 1 gallon = 3.785 liters?
A 1,324.75 milliliters
B 13,247.5 milliliters
C 132,475 milliliters
D 1,324,750 milliliters
Mathematics
2 answers:
son4ous [18]2 years ago
8 0

Answer:

b

Step-by-step explanation:

hope this helped you!!

baherus [9]2 years ago
3 0

1 gallon = 3.785 liters

 3.5 * 3.785 = 13.2475 total liters

1 liter = 1000 milliliters

13.2475 * 1000 = 13,247.5 milliliters

 Answer is B

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Donald has xxx twenty-dollar bills and 111 ten-dollar bill. How much money does Donald have? Write your answer as an expression.
dexar [7]

Answer:

20x + 10

Step-by-step explanation:

Given that :

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Hence,

($20 * x) + ($10 * 1)

20x + 10

The expression for the amount of money Donald has is : 20x + 10

3 0
1 year ago
One of the sides of a parallelogram is 4.2 cm and the altitude to that side is 3.6 cm. Find the perimeter of the parallelogram i
dexar [7]

Area of parallelogram = base * height
base 1 = 4.2 cm
height 1 = 3.6 cm
∴ Area = 4.2 * 3.6 = 15.12

let the other base 2 = x
∴ the altitude of this base = height 2 = 2.4
∴Area = 2.4 x = 15.12
Solve for x
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7 0
2 years ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
2 years ago
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