Bvgdgmhmgjm,jh,,,,,,,,,,,,,,,,,
Answer:
Step-by-step explanation:
Given;
a)
substitute 
b)
Apply partial fraction in (a), we get;
where C is an arbitrary constant
Answer:
0.84 square in
Step-by-step explanation:
Since the capacity of the cable is proportional to its cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold
2500 / 0.3 = 8333.33 lb/in
To old 7000 lb it the cross-sectional area would need to be
7000 / 8333.33 = 0.84 square in
2x + 2x +2 are the integers
4x^2 + 4x^2 +8x +4 =884 (The sum of the integers squared)
8 x^2 +8x -880 = 0
x = 10
Therefore, the integers are:
20 and 22
