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Stells [14]
2 years ago
14

How many hydrogen atoms are in 0.1488 g of phosphoric acid, H3PO4?

Chemistry
2 answers:
Dahasolnce [82]2 years ago
4 0

Answer:

The answer to your question is:  2.75 x 10 ²¹ atoms

Explanation:

Data

H₃PO₄

mass = 0.1488 g

MW H₃PO₄ = 3 + 31 + (16 x 4) = 98g

                         98 g of H₃PO₄ ------------------  3 g of H₂

                         0.1488 g H₃PO₄ ---------------   x

                         x = 0.0046 g of H₂

                         1 g of H₂      ------------------- 6.023 x 10²³ atoms

                         0.0046 g of H₂ --------------   x

                         x = (0.0046 x 6.023 x 10²³) / 1

                         x = 2.75 x 10 ²¹ atoms

AveGali [126]2 years ago
4 0
I know god he came to me
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Explanation:

CHECK THE ATTACHMENT FOR THE COMPLETE QUESTION AND THE DETAILED EXPLANATION

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2 years ago
In the adjoining figure, the circles with the + sign represent protons and the empty circles represent neutrons. Determine which
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Answer: option C. 2 and 3.

Explanation:

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3) In the figure there are 3 different atoms:

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2 years ago
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Answer:

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4.925g of disodium succinate.

Explanation:

To find pH of the buffer produced by the mixture of monosodium succinate-Disodium succinate is obtained from H-H equation:

pH = pKa + log ([Na₂Suc] / [NaHSuc])

As you want a pH of 5.28 and pKa is 5.64:

5.28 = 5.64 + log ([Na₂Suc] / [NaHSuc])

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<em />

As total concentration of the buffer is 100mM = 0.100M:

0.100M = [Na₂Suc] + [NaHSuc] <em>(2)</em>

Replacing (2) in (1):

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

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1.4365 [NaHSuc] = 0.100M

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As volume of the buffer is 1L:

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Mass of disodium succinate:

0.0304moles * (162g / 1mol) =<em> 4.925g of disodium succinate.</em>

<em></em>

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