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2 years ago

Which sentence best reflects a theme in, "The Piece of String" by Guy de Maupassant? (PLZZZ HELPPP)

Mathematics

2 answers:

Mariulka [41]2 years ago

8 0

The answer is

(c) innocence is hard to prove without trust

Hope this helps :3

Ket [755]2 years ago

4 0

Answer:

the answer is D innocence is hard to prove without trust.

Step-by-step explanation:

does anyone go to AZVA?

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How many solutions are there to the system of equations?

hichkok12 [17]

Answer: The system of equations has NO SOLUTION.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

Given the following system of equations:

$\left \{ {{4x-5y=5} \atop {-0.08x+0.10y=0.10}} \right.$

Write the first equation and solve for "y" in order to express it in Slope-Intercept form:

$4x-5y=5\\\\-5y=-4x+5\\\\y=\frac{-4x}{-5}+\frac{5}{-5}\\\\y=0.8x-1$

You can identify that:

$m=0.8\\b=-1$

Apply the same procedure with the second equation. Then:

$-0.08x+0.10y=0.10\\\\0.10y=0.08x+0.10\\\\y=\frac{0.08x}{0.10} +\frac{0.10}{0.10}\\\\y=0.8x+1$

You can identify that:

$m=0.8\\b=1$

The slopes of both lines are equal, therefore the lines are parallel and the system has NO SOLUTION.

7 0

2 years ago

Read 2 more answers

The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in

Marina86 [1]

Answer:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

$\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3$

We can express this formula like this:

$\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

$\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

If we operate and we take out the 1/4 as a factor we got this:

$\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}$

We can cancel $n^2$ and we got

$\lim_{n\to\infty} \frac{(n+1)^2}{n^2}$

We can reorder the terms like this:

$\lim_{n\to\infty} (\frac{n+1}{n})^2$

We can do some algebra and we got:

$\lim_{n\to\infty} (1+\frac{1}{n})^2$

We can solve the square and we got:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

3 0

2 years ago

If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?

Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are $c(x) = \frac{5}{x - 2}$ and d(x) = x + 3

So, (cd)(x) = $(\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}$

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

8 0

2 years ago

Read 2 more answers

In a survey conducted with 600 participants across the United States, 450 were found to have studied science in college. If we w

Dahasolnce [82]

Confidence interval of a population proportion is given by p^ + or - sqrt(p^(1 - p^)/n); where p^ = 450/600 = 0.75 and n = 600
99.7% convidence interval = 0.75 + or - 2.96 x sqrt(0.75(1 - 0.75)/600) = 0.75 + or - 2.96 x sqrt(0.75(0.25)/600) = 0.75 + or - 2.96 x 0.0177 = 0.75 + or - 0.0524 = 0.697 to 0.803 = 69.7% to 80.3%

7 0

2 years ago

Ajay is researching how the population of his hometown has changed over time. Specifically, he learns his hometown had a populat

777dan777 [17]

Answer:

Could you Write the question more clearly?

Step-by-step explanation:

7 0

2 years ago