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ozzi
2 years ago
13

In a survey conducted with 600 participants across the United States, 450 were found to have studied science in college. If we w

ere to predict the population proportion with a 99.7% confidence, what would the confidence interval be? A. 69.7% to 80.3% B. 73.23% to 76.76% C. 71.46% to 78.53% D. 73.5% to 76.5%
Mathematics
1 answer:
Dahasolnce [82]2 years ago
7 0
Confidence interval of a population proportion is given by p^ + or - sqrt(p^(1 - p^)/n); where p^ = 450/600 = 0.75 and n = 600
99.7% convidence interval = 0.75 + or - 2.96 x sqrt(0.75(1 - 0.75)/600) = 0.75 + or - 2.96 x sqrt(0.75(0.25)/600) = 0.75 + or - 2.96 x 0.0177 = 0.75 + or - 0.0524 = 0.697 to 0.803 = 69.7% to 80.3%
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It is known that driving can be difficult in regions where winter conditions involve snow-covered roads. For cars equipped with
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Answer:

The null and alternative hypothesis for this test are

H_0: \mu\ge 215\\\\H_1: \mu< 215

Step-by-step explanation:

If we perform a hypothesis test, we can reject or not reject the null hypothesis.

To conclude that the tires have a decreased stopping distance (μ<215), we should state the null hypothesis H_0: \mu\ge 215 and then go on with the analysis to reject it (or not).

If the null hypothesis is rejected, the claim of the manufacturer is rigth.

The alternative hypothesis would be H_1: \mu, that would turn rigth if the null hypothesis is rejected.

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2 years ago
The expression x4 + 6x3 – 11x2 – 60x + 100 is equivalent to (x – 2)(x – 2)(x + 5)(x + 5). At what points does the graph of the f
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Since y equals the product of the factors, any value for x which makes any factor equal to zero is a point where the graph touches the x-axis.

x=-5 and 2  (technically the points (-5,0) and (2,0))
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2 years ago
Read 2 more answers
A candy store sells caramels and milk chocolate by the pound the table below shows the total cost in dollars for a pound of each
MakcuM [25]

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Step-by-step explanation:

Given,

Cost of one pound of Caramels = $10.28

Cost of 1\frac{3}{4} pounds of Caramel = 10.28*1\frac{3}{4}

Cost of 1\frac{3}{4} pounds = 10.28*\frac{7}{4}=\frac{71.96}{4}= \$17.99

Cost of one pound of chocolate milk = $13.85

Cost of 1\frac{3}{4} pounds = 13.85*1\frac{3}{4}=13.85*\frac{7}{4}

Cost of 1\frac{3}{4} pounds = \frac{96.95}{4}=\$24.24

Difference = 24.24 - 17.99 = $6.25

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Keywords: difference, multiplication

Learn more about multiplication at:

  • brainly.com/question/10414011
  • brainly.com/question/10483199

#LearnwithBrainly

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1 year ago
1.Write down the short-hand for these two normal distributions. The Verbal Reasoning section has a distribution N( , ) The Quant
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Answer:

Step-by-step explanation:

4 0
2 years ago
A student club holds a meeting. The predicate M(x) denotes whether person x came to the meeting on time. The predicate O(x) refe
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Answer:

a) \exists \, x \in C : O(x) = 0

b) \{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) \{ x \in C: M(x) = 1 \} = C

d) \{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) \exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) \exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

Step-by-step explanation:

  • M(x) = 1 if the person x came to the meeting, and 0 otherwise.
  • O(x) = 1 if the person is an officer of the club and 0 otherwise.
  • D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.

Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.

a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way

\exists \, x \in C : O(x) = 0

b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:

\{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:

\{ x \in C: M(x) = 1 \} = C

d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:

\{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore

\exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have

\exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

I hope that works for you!

7 0
2 years ago
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