D^2=x^2+y^2
d^2=(310+150cos20)^2+(150sin20)^2
d^2=205991.41373309
d=453.86mi
So C. to the nearest mile.
First find the mean (sum divided by number of values)
4+5+8+10+15=42
42/5=8.4
Then find the difference between each of the numbers and the mean.
4.4, 3.4, 0.4, 1.6, 6.6
Then find the mean of those values.
4.4+3.4+0.4+1.6+6.6=16.4
16.4/5=3.28
Final answer: 3.28
Answer:
None of the above
Step-by-step explanation:
Answer: Time t = 33.0 seconds
Step-by-step explanation:
Given that the vertical distance H between the dock and the top of the boat's mast t seconds after its first peak is modeled by the function
H(t) = 5cos( 2π/3 t) − 35.5H
Where the maximum vertical distance = 5
At the down position, H(t) = 0
5cos( 2π/3 t) − (35.5/100)H = 0
5cos( 2π/3 t) − 0.355 × 5 =0
5cos( 2π/3 t) − 0.1775 = 0
5cos( 2π/3 t) = 0.1775
cos( 2π/3 t) = 0.1775/5
cos( 2π/3 t) = 0.355
2π/3 t = cos^-1 (0.355)
2π/3 t = 69.2
2πt = 69.2 × 3
2πt = 207.6
t = 207.6/2π
t = 33.0 seconds
Answer:
Musah's final point from the centre = 60.355 steps
Step-by-step explanation:
From the given information:
Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps west and finally 50 steps on a bearing of 315°
The sketch for this information can be seen in the attached file below.
How far west is Musah's final point from the centre?
In order to determine how far west is Musah's,
Let d be the distance of how far;
Then d = QR + RS cos θ
In the North West direction,
cos θ = cos 45°
d = 25 + 50( cos 45°)
d = 25 + 50(
)
d = 25 + 50( 0.7071)
d =25 + 35.355
d = 60.355 steps
Musah's final point from the centre = 60.355 steps