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Mice21 [21]
2 years ago
13

Describe how total job benefits and total employee compensation differ.

Mathematics
1 answer:
diamong [38]2 years ago
5 0

<u>Difference between total job benefits and total employee compensation:</u>

<em>Employee compensation:</em>

  • The total employee compensation refers to the amount of money an employee is given in exchange for the tasks they complete for the employer.
  • Employee compensation is the most basic or we can say the minimum amount of money an employee is given. It mostly includes the salary of an employee.

<em>Total job benefits:</em>

  • Total job benefits are not necessarily provided in monetary means. As the name suggests, job benefits are the facilities and advantages provided by the company or the employer to the employees.
  • These benefits are generally performance- based, the better the performance, the better the benefits.
  • Job benefits may include health insurance policies, travel packages, transport facilities and much more.

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A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram
azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The standard deviation of sample mean is inversely proportional to the sample size, <em>n</em>.

So, if <em>n</em> increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of <em>n</em> from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for <em>n</em> = 64 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7

The standard deviation of the sample mean for <em>n</em> = 196 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4

The standard deviation of the sample mean decreased from 0.7 to 0.4 when <em>n</em> is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of <em>n</em> from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for <em>n</em> = 784 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2

The standard deviation of the sample mean for <em>n</em> = 49 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8

The standard deviation of the sample mean increased from 0.2 to 0.8 when <em>n</em> is decreased from 784 to 49.

Hence, the variance also increases.

6 0
2 years ago
Mika used division to rewrite 5/40
ella [17]
Hello there, and thank you for posting your question here on brainly.

To convert a decimal to a percent, you have to make the decimal a whole number by getting rid of the decimal point, and then at a % sign.

0.125 ===> 125

125 ===> 125%

Hope this helped!! ☺♥
7 0
2 years ago
Read 2 more answers
Which rule describes the composition of transformations that maps pre-image ABCD to final image A"B"C"D"? Reflection across the
NeTakaya

Answer:

Your answer is the first point

A reflection across the x-axis and then a transformation of -6 and 1.

7 0
2 years ago
The graph shows a distribution of data.
ss7ja [257]

Answer:

.0625 or A

Step-by-step explanation:

You have to work out the mean. (The simple average of those numbers) Then for each number subtract the Mean and square the result. Then work out the average of those squared differences.

5 0
2 years ago
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A machine takes 5.4 hours to make 9 parts. At that rate how many parts can the machine make in 25.8 hours
Sliva [168]
\frac{5.4}{9} = \frac{25.8}{x}    Cross multiply.

5.4x=9*25.8

5.4x=232.2    Divide both sides by 5.4

x=43
4 0
2 years ago
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