This is done by a very simple formula: the only thing you need to type is =x-y where x is the cell that contains the total of 2018 and y being the cell that contains the total for 2017. If both are numeric values you can use the formula = A1-B1 and get your result. Your <span>cells don't have to be in the same order as your formula.</span>
Answer: *use the last column for text with multiple lines.
*use an indent marker to indent the first line of a paragraph.
*use a table if text in multiple columns have multiple lines.
Explanation:
Answer:
a. WS-Trust
Explanation:
WS-Trust can be defined as a WS-specification as well as OASIS standard that help to provides extensions to WS-Security, in order to facilitate a mechanism for issuing, renewing, as well as validating of security tokens which is why the aim and objectives of WS-Trust is to help and enable applications to construct trusted SOAP message exchanges.
Nevertheless WS-Trust enables the issuance as well as the dissemination of credentials within several and various trust domains.
Answer:
#include <iostream>
using namespace std;
void CoordTransform(int *ptr1, int *ptr2);
int main()
{
int xVal;
int yVal;
cout<<"please enter two valid integers";
cin>>xVal;
cin>>yVal;
CoordTransform(&xVal , &yVal);
int xValNew=xVal;
int yValNew=yVal;
cout<<xValNew<<yValNew;
return 0;
}
void CoordTransform(int *ptr1, int *ptr2)
{
int a = *ptr1;
*ptr1=(*ptr1+1)*2;
*ptr2=(*ptr2+1)*2;
}
Explanation:
It will return new values in previously defined variables
coding language: c++
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
