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2 years ago

A toy car costing $50 is reduced by 10% in the sale. How much does it cost now? Show me your work plz

Mathematics

2 answers:

densk [106]2 years ago

7 0

Answer:

Now it costs $45.

Step-by-step explanation:

I'll show you two different ways of doing it.

Method A. Find the dollar mount of the discount and subtract it from the original price.

The percent discount is 10%.

First, we find 10% of $50.

10% of $50 = 10% * $50 = 0.1 * $50 = $5

The dollar amount of discount is $5.

Now we subtract the dollar amount of the discount from the original price.

$50 - $5 = $45

Answer: Now it costs $45.

Method B. Find the percent of the discounted price and use it to find the discounted price.

The original price, $50, is 100% of the original price since 100% is the entire thing. The discount is 10%, so we subtract 10% from 100%.

100% - 10% = 90%

After you take off 10% from the original price, the discount price is only 90% of the original price. Now we find 90% of $50.

90% of $50 = = 90% * $50 = 0.9 * $50 = $45

Answer: Now it costs $45.

wlad13 [49]2 years ago

5 0

Answer:

$45

Step-by-step explanation:

divide 50 by 100 (as in 100%) then multiply it by 90 (as in 90%)

50 ÷ 100 × 90 = 45

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2 years ago

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Answer:

The value of the test statistic is t=1.12.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the mean amount of time required to reach a customer service representative significantly differs between the two hotels.

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$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

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The sample 2, of size n2=20 has a mean of 2.01 and a standard deviation of √2.952=1.89.

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The estimated standard error of the difference between means is computed using the formula:

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2 years ago

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Answer:

r = 2 units

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Step-by-step explanation:

Given That:

Cones A and B both have volume cubic 48π units

The volume of a cone = $\frac{1}{3} \pi r^2h$

So for cone A

$V_A = \frac{1}{3} \pi r_A^2 h_A$

Volume for cone B

$V_B = \frac{1}{3} \pi r_B^2 h_B$

Due to different dimensions;

Cone A has

radius = 6 units

height = 4 units

To determine the one possible radius and height for cone B;

we have

$\frac{1}{3} \pi r_A^2 h_A =\frac{1}{3} \pi r_B^2 h_B$

$\frac{1}{3} \pi (6)^2 (4) =\frac{1}{3} \pi r_B^2 h_B$

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If we are to check: we will realize that;

$r_B^2h_B = (2)^2*36 =144$

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Answer:

Please see the attachment for double number line.

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