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Mandarinka [93]
2 years ago
8

As a part-time contractor, you want to test a new cement mixture for a project. You need 2 34 wheelbarrows of sand to make 8 whe

elbarrows of concrete. How much sand will you need to make 248 cubic feet of concrete?
Mathematics
2 answers:
romanna [79]2 years ago
7 0

Answer: He would need 10.07 cubic feet of sand for wheelbarrows.

Step-by-step explanation:

Since we have given that

Ratio of wheelbarrows of sand to wheelbarrows of concrete is given by

2\dfrac{3}{4}:8\\\\=\dfrac{11}{4}:8\\\\=11:32

Volume of concrete for wheelbarrows = 248 cubic feet.

Then volume of wheelbarrows of sand would be

(\dfrac{11}{32})^3=\dfrac{x}{248}\\\\\dfrac{1331\times 248}{32^3}=x\\\\10.07=x

Hence, he would need 10.07 cubic feet of sand for wheelbarrows.

nirvana33 [79]2 years ago
6 0

Answer: 85 1/4 cubic feet

Step-by-step explanation:

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2 years ago
How many solutions does the system have? { y = − 7 x + 8 y = − 7 x − 8 ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ y=−7x+8 y=−7x−8 ​
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3 0
2 years ago
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A rectangular area is formed having a perimeter of 40 cm. Determine the length and breadth of the rectangle if it is to enclose
Vilka [71]

Let x and y be the dimensions of the rectangle. If the perimeter is 40, we have

2(x+y)=40 \iff x+y=20

We can expression one variable in terms of the others as

x+y=20 \iff x=20-y

Since the area is the product of the dimensions, we have

xy=(20-y)y=-y^2+20y

This is a parabola facing down, so it's vertex is the maximum:

f(y)=-y^2+20y \implies f'(y)=-2y+20

So, the maximum is

f'(y)=0 \iff -2y+20=0 \iff 2y=20 \iff y=10

And since we know that x+y=20, we have x=10 as well.

This is actually a well known theorem: out of all the rectangles with given perimeter, the one with the greatest area is the square.

5 0
2 years ago
Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

So, remainder is 13 and -13.

5 0
2 years ago
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tamaranim1 [39]
<span>Let be A =a3b +9a2b2-4ab5, and B=a3b-3a2b2+ab5,so the difference can be defined as A - B =a3b +9a2b2-4ab5 -(a3b-3a2b2+ab5), when there is negative sign in front of the parathesis, all the inside signs must change: that is as follow: A- B= a3b +9a2b2-4ab5 - a3b + 3a2b2 - ab5= a3b-a3b +9a2b2+3a2b2-4ab5- ab5= 12a2b2 -5ab5, the fist term has 2+2=4, as a degree,the second term has 1 +5 =6, so the true answer : The difference is a binomial with a degree of 6</span>
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2 years ago
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