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Oxana [17]
2 years ago
15

35. Chebychey's Theorem Old Faithful is a famous geyser at Yellowstone National Park. From a sample with 32. the mean duration o

f Old Faithful's eruptions is 3.32 minutes and the standard deviation is 1.09 minutes. Using Chebycher's Theorem, determine at least how many of the eruptions lasted between 1.14 minutes and 5.5 minutes. (Source: Yellowstone National D 36. Chebycher's Theorem The - 577

Mathematics
1 answer:
spayn [35]2 years ago
5 0

Answer:

The probability that the eruptions lasted between 1.14 min and 5.5 minutes is greater than 75%

Step-by-step explanation:

The explanation can be found in the attached picture. Chebyshev's <u>inequality </u>was used. It predicts the probability of the random variable to be in ( mean- K* standard dev< x < mean + K*standard dev).

Note: K must be greater than 1

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Answer:

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Step-by-step explanation:

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The combined rate is
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BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

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on integrating we get

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b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

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                        =0.37349

c)

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f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

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f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

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e)

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f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

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Answer:

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