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Oxana [17]
2 years ago
15

35. Chebychey's Theorem Old Faithful is a famous geyser at Yellowstone National Park. From a sample with 32. the mean duration o

f Old Faithful's eruptions is 3.32 minutes and the standard deviation is 1.09 minutes. Using Chebycher's Theorem, determine at least how many of the eruptions lasted between 1.14 minutes and 5.5 minutes. (Source: Yellowstone National D 36. Chebycher's Theorem The - 577

Mathematics
1 answer:
spayn [35]2 years ago
5 0

Answer:

The probability that the eruptions lasted between 1.14 min and 5.5 minutes is greater than 75%

Step-by-step explanation:

The explanation can be found in the attached picture. Chebyshev's <u>inequality </u>was used. It predicts the probability of the random variable to be in ( mean- K* standard dev< x < mean + K*standard dev).

Note: K must be greater than 1

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Jimmy will be selling hot dogs at the football game. He bought hot dogs, buns, and condiments for a total of \$8$8dollar sign, 8
attashe74 [19]

Answer:

The correct way to complete the sentences is as follows:

As Jimmy sells more hot dogs, his profit will increase.

Jimmy sells the hot dogs for $1 each.

Jimmy needs to sell 8 hot dogs to recover the money he invested.

If Jimmy sells 15 hot dogs, he will make $7 in profit.

To make $12 in profit, Jimmy would have to sell 20 hot dogs.

3 0
2 years ago
On a road map, the locations A, B and C are collinear. Location C divides the road from location A to B, such that AC:CB = 1:2.
koban [17]

Answer:

C. (-1,-2)

Step-by-step explanation:

Since C internally divides AB in the ratio AC/CB = 1/2 = m/n where m = 1 and n = 2, we use the formula for internal division.

Let A = (x₁, y₁) = (5, 16), B = (x₂, y₂) and C = (x, y) = (3, 10)

So x = (mx₂ + nx₁)/(m + n)

y = (my₂ + ny₁)/(m + n)

Substituting the values of the coordinates, we have

x = (mx₂ + nx₁)/(m + n)

3 = (1 × x₂ + 2 × 5)/(2 + 1)

3 = (x₂ + 10)/3

multiplying through by 3, we have

9 = x₂ + 10

x₂ = 9 - 10

x₂ = -1

y = (my₂ + ny₁)/(m + n)

10 = (1 × y₂ + 2 × 16)/(2 + 1)

10 = (x₂ + 32)/3

multiplying through by 3, we have

30 = y₂ + 32

y₂ = 30 - 32

y₂ = -2

So, the coordinates of B are (-1, -2)

3 0
2 years ago
How much water do you add  to make 12% sugar syrup using 5g sugar?
Alchen [17]

so the syrup is just water and sugar, we know that the sugar percent is just 12%, and that happens to be 5grams.

now 100% - 12% is 88%, so the 88% leftover will just be water.

if 12% is 5g, how much is 88%?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 5&12\\ x&88 \end{array}\implies \cfrac{5}{x}=\cfrac{12}{88}\implies \cfrac{5}{x}=\cfrac{3}{22}\implies 110=3x \\\\\\ \cfrac{110}{3}=x\implies 36\frac{2}{3}=x

8 0
2 years ago
Read 2 more answers
Mike and Krista rent a jet ski while on vacation. The rental cost is represented by the function c(h)=50+20h, where the number o
Step2247 [10]

Answer:

130

Step-by-step explanation:

Given the equation of the relation as c(h) =50 +20 h where c(h) is the total cost for h hours and h is the number of hours of use, then to find the cost of jet ski if 4 hours were used will be;

c(h)=50 +20 h

c(4)=50 +20*4

c(4)=50 +80

=130

5 0
2 years ago
The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda
blondinia [14]

Answer:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

\mu = 514 , \sigma =40

For this case we can use the Chebysev theorem who states that "At least 1 -\frac{1}{k^2} of the values lies between \mu -k\sigma and \mu +k\sigma"

And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

4 0
2 years ago
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