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2 years ago

A softball home plate has been designed on the coordinate plane shown below

Mathematics

1 answer:

Leno4ka [110]2 years ago

4 0

If there is a picture please include it and i’ll be happy to help!

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The velocity of a ball is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average acceler

Reptile [31]

Average acceleration: ( v - v o ) / Δ t
v = 0 m/s, v o = 20 m/s, Δ t = 3.5 s
a (average) = ( 0 m/s - 20 m/s )/3.5 s = - 20 m/s / 3.5 s =
= - 5.7142857 m/s² ≈ - 5.71 m/s²

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2 years ago

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Bill's favorite breakfast cereal is available in four different sizes. Which is the best buy?

Alex787 [66]

Answer:

The best deal is the 18 ounce box

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2 years ago

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Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

4 0

2 years ago

Which inference is true?

Musya8 [376]

Answer:

The answer is c

I just answered the question on edunity

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2 years ago

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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,

grandymaker [24]

Solution:

There is no saddle point (DNE). However, there is local maximum at (1, 1/2) for the given function.

Explanation:

we have function of two variables f(x,y)= 9-2x+4y-x^2-4y^2

we will find the values by partial derivative with respect to x,y,xy

$f_{x}$ = -2 -2x

$f_{y}$ = 4 -8y

to find the saddle point we should first find the critical points so equate

-2 -2x=0 and 4 -8y=0

we get x= 1 and y =1/2 so, critical points are (1,1/2)

to find local maximum or minimum we have to find $f_{xx}$ , $f_{yy}$ and $f_{xy}$

formula is $f_{xx}$ * $f_{yy}$ - $f^{2_{xy} }$ =0

$f_{xx}$ = -2

$f_{yy}$ = -8

$f^{2_{xy} }$ =0

putting values in formula

(-2)*(-8) -0 =16 > 0, and $f_{xx}$ < 0 and $f_{yy}$ <0

so, here we have local maximum

we have no saddle point for this function by using the same formula we used to find extrema.

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2 years ago

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