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SSSSS [86.1K]
2 years ago
13

A scientist has an uncharacterized pea plant. She wants to determine the plant’s genotype for seed color. In order to be certain

that she will get conclusive results from a single cross, with what plant could she cross it?
Biology
1 answer:
aleksklad [387]2 years ago
7 0

Answer:

Recessive phenotype plant

Explanation:

If the plant has recessive genotype then it will be easy to identify because it will have the recessive phenotype. However if the plant has dominant phenotype it can either have homozygous genotype or heterozygous genotype. To confirm if the plant is homozygous or heterozygous, a test cross can be done with plant having recessive phenotype.

If our test plant is homozygous dominant, it will pass one dominant allele to the next generation and all the offspring would have dominant phenotype. If our test plant is heterozygous dominant it will pass one dominant allele to half of the offspring and one recessive allele to another half so 50% of next generation will have dominant phenotype and other 50% will have recessive phenotype.

Hence by test cross (cross with recessive phenotype plant) it is possible to determine the genotype of the uncharacterized pea plant.

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Leokris [45]

Answer:

Because DNA polymerase can synthesize DNA strands in 5' to 3' direction only.

Explanation:

The 5' end of one DNA strand is present opposite to the 3' end of the other strand. But DNA polymerase enzyme can elongate the primers in 5' to 3' direction only. Formation of a phosphodiester bond between the existing nucleotide and the incoming nucleotide requires the free 3'OH. This 3' OH serves in the nucleophilic attack during the formation of the bond.

Therefore, the lagging strand is synthesized discontinuously in the form of short DNA fragments. These are called Okazaki fragments. Primers are formed for short distances which in turn are elongated by DNA polymerase to form the Okazaki fragments. On the other hand, the synthesis of the leading strand occurs continuously in the same direction in which the replication fork moves.

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2 years ago
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