Answer: 2
<u>Explanation:</u>
A pond had 60 fish but 10 were added so now the pond has 70 fish.
The probability of choosing a carp is 1/2 so 
= 35 are now carp.
There were 27 carp and now there are 35 carp so 8 carp were added.
10 fish were added and 8 of them were carp so 2 of them were tench.
A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100
<span>0.00020869565 - that is the whole answer, but if you were to round to the nearest tenth it would be 0.0</span>
It can't be A. since if you only look at managers, you are missing all the sales executives.
It may be C. this option is more random but doesn't guarantee that you will represent both groups of employee's. Also, each time you would conduct the survey, you will receive the exact same results since it is the same people.
It isn't D. for the exact same reason as A. but you're missing managers now.
Therefore the answer is B. Some managers and some sales executives selected at random. This way you get a sample from both categories, and within those groups, it is randomly selected.
I hope this helps!
The answer
the table is
x 0 1 4 5 7
y 3 1 0 -2 -2
<span>the approximate line of best fit to be y = –0.7x + 2.36
so when the value of x=5, the residual value is
</span><span>y = –0.7(5) + 2.36 = -1.14 this is the actual value
the predicted value is -2 (for x=5)
and residual value formula is RS = y actual value - y predicted value
so RS = -1.14 - (-2) = 0.86
</span>
