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UkoKoshka [18]
1 year ago
7

The owner of an office building is expanding the length and width of a parking lot by the same amount. The lot currently measure

s 120 ft by 80 ft, and the expansion will increase its area by 4,400 ft^2. How many feet should the length of the parking lot be increased?
A) 1.2
B) 20
C) 66.3
D) 220
Mathematics
2 answers:
Goryan [66]1 year ago
7 0

Answer: B) 20

Step-by-step explanation:

edg 2020

Gnoma [55]1 year ago
4 0

The best and most correct answer among the choices provided by your question is the second choice or letter B "20".

The current area is 120(80)=9600 and he want to expand it by 4400 so that the new area will be 9600+4400=14000 

14000=(120+x)(80+x) 

14000=9600+200x+x^2 

x^2+200x-4400=0 

x^2-20x+220x-4400=0 

x(x-20)+220(x-20)=0 

(x+220)(x-20)=0, since x is an increase it must be greater than zero so 

x=20ft 

(120+20)(80+20)=14000ft^2


I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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Last year Boris paid £256 for his car insurance.
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The percentage increase in the cost of Boris car insurance cost is 249%

Step-by-step explanation:

In this question, we want to calculate the percentage increase in the cost of car insurance paid by Boris

Mathematically, to calculate this percentage increase, we shall need to make use of a mathematical formula.

Mathematically, the percentage increase would be;

{(new value paid-old value paid)/old value paid} * 100%

From the question, we can identify that the old value paid is £256 while the new value paid is £894

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2 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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  • 2 must be related with 2,
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For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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Since, the number w and 0.8 are additive inverses.

A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".

Since, 'w' and '0.8' are additive inverses of each other such that w + 0.8 = 0

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