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UkoKoshka [18]
1 year ago
7

The owner of an office building is expanding the length and width of a parking lot by the same amount. The lot currently measure

s 120 ft by 80 ft, and the expansion will increase its area by 4,400 ft^2. How many feet should the length of the parking lot be increased?
A) 1.2
B) 20
C) 66.3
D) 220
Mathematics
2 answers:
Goryan [66]1 year ago
7 0

Answer: B) 20

Step-by-step explanation:

edg 2020

Gnoma [55]1 year ago
4 0

The best and most correct answer among the choices provided by your question is the second choice or letter B "20".

The current area is 120(80)=9600 and he want to expand it by 4400 so that the new area will be 9600+4400=14000 

14000=(120+x)(80+x) 

14000=9600+200x+x^2 

x^2+200x-4400=0 

x^2-20x+220x-4400=0 

x(x-20)+220(x-20)=0 

(x+220)(x-20)=0, since x is an increase it must be greater than zero so 

x=20ft 

(120+20)(80+20)=14000ft^2


I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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127.90 in expanded form:


100 + 20 + 7 + 0.9

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1 year ago
The maximum grade allowed between two stations in a​ rapid-transit rail system is​ 3.5%. Between station A and station​ B, which
saveliy_v [14]

Answer:

x = 3.1 %

Step-by-step explanation:

Let x be the slope the track.

Given:

Distance between station A and B = 270 ft

Track rise = 8\frac{1}{2} = \frac{17}{2} = 8.5\ ft

We need to find the slope of the railway track between station A an B.

Solution:

The maximum grade allowed between two stations in a​ rapid-transit rail system is​ 3.5%.

We know that slope of the railway track is equal to gradient of the tracks.

So. the slope of the railway track is defined as the ratio of the distance between the stations and track rises.

Slope\ of\ the\ the\ tracks =\frac{Distance\ between\ two\ stations}{track\ rises}

x=\frac{8.5}{270}\times 100

x = 3.1 %

So x = 3.1 % less than the maximum grade allowed between two stations in a​ rapid-transit rail system is​ 3.5%.

Therefore, x = 3.1 % meets the​ rapid-transit rail​ standards.

5 0
1 year ago
A recipe calls for 1 part beans to 1½ parts rice. If 1½ parts of beans are used, how much rice should be used?
marshall27 [118]

Answer:

2.

Step-by-step explanation:

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7 0
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A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
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8,000 is blank as 800
Alecsey [184]

8,000 is 10 times as much as 800

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