Answer:
c. Involvement and empowerment of employees at all levels
Explanation:
Total quality management refers to managing the organization in order to develop a success in the long run by considering the low level workers to the high level executive, and at the same time focused on quality improvement and the customer satisfaction
Here are the following points to become important for an organization
1. Quality improvement, management leads to long term success for organization and customers
2. The deficiencies could be determined by performing the work and can be corrected through providing the training, education, etc
3. If the product contains high quality that meet the needs of the customers than it would lead to high customer satifaction
4. And, in case if there is few defective product so the company is in a position to save the cost
Answer:
$204,080
Explanation:
The computation of operating cost is shown below:-
operating cost if occupy 55%
Cost on (800 × 90%)
= 720 units is $220,040
Cost on (800 × 80%)
= 640 Units is $215,480
Variable cost per unit = Changes in total cost ÷ High activity-Low activity
= ($220,040 - $$215,480) ÷ (720 - 640)
= 4,560 ÷ 80
= 57 per unit
Fixed cost = Total cost - Variable cost
= $220,040 - (720 × 57)
= $179,000
Cost equation:
Total cost = Fixed cost + Variable cost per unit
Y = $179,000 + 57X
Y = $1790,00 + (57 × 440)
Y = $204,080
Answer:
b) policies and procedures manual.
Explanation:
A company's policies and procedures manual is essential for establishing norms and rules that will guide the company's operation.
Through corporate policies, it is possible to determine actions, conducts, practices and values that the company adopts in order to achieve its objectives and goals, and demonstrate what are its fundamental values that give this organization its own identity and the foundations that will make it different from other companies in the competitive market.
Answer:
Explanation:
Given:
Selling price of 1 lamp = $6
Cost price of 1 lamp = $4
Units sold per month = 3000
Let $T be the selling price set by the lamp seller.
Number of sold lamps per month = 3000 − (T − 6) × 1000
= 9000 − 1000 × T.
Monthly profit = (9000 − 1000p) × (T − 4)
= −1000T^2 + 13000T − 36000.
Obtaining the derivative,
dS/dT = −2000T + 13000
and setting it to zero
−2000T + 13000 = 0
T = -13000/-2000
optimal selling point, T = $6.5.