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posledela
2 years ago
4

If you dissolve 24.4 g of NaCl in 251 g of water and generate a solution that has a density of 1.10 g/mL, what is the molarity o

f NaCl in this solution? Enter a numerical value in the correct number of significant figures. Do not enter units in the answer box, but understand that the unit needed for the final answer is M.
Chemistry
1 answer:
Zina [86]2 years ago
7 0

Answer:

The molarity of this NaCL solution is 1.83 M:

Explication:

<u>Step 1:</u> Data  given

Mass of NaCl = 24.4 grams

Mass of water = 251 grams

Density of water = 1.10 g/mL

<u>Step 2: </u>Calculate volume of water

Volume of water = Mass of water / density of water

Volume of water = 251 grams / 1.10 g/mL

Volume of water = 228.18 mL =0.22818L

<u>Step 3:</u> Calculate moles NaCl

Number of moles NaCl = 24.4 grams / 58.44 g/mol

Number of moles = 0.4175 moles

<u>Step 4:</u> Molarity of the solution

Molarity = Number of moles / Volume

Molarity = 0.4175 moles / 0.22818 L

Molarity = 1.83 M

The molarity of this NaCL solution is 1.83 M

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H+/PO-4^-2

Explanation:

hydrogen has dissolved completely

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2 years ago
If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximat
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Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

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8 0
2 years ago
In a study of the decomposition of the compound XX via the reaction
Leya [2.2K]

Answer:

( About ) 0.03232 M

Explanation:

Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [X_o]"

This formula would be true for the following information -

{ X_o = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }

________

Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6

1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X

1 / [X] = 28.8 + 1 / ( 0.467 ),

1 / [X] = 28.8 + 2.1413...,

1 / [X] = 31,

[X] = 1 / 31 = ( About ) 0.03232 M

Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M

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2 years ago
If 1.00 mol of argon is placed in a 0.500-L container at 19.0 ∘C , what is the difference between the ideal pressure (as predict
lana66690 [7]

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