Transformation on y=-(x-2)

A jar contains black marbles and green marbles. Sixty percent of the marbles in the jar are green. A number generator simulates

grigory [225]

Answer: D

Step-by-step explanation:

The number generator is not fair, in most of the experiments, considerably less than 60 % of the selected marbles are green.

And if Sixty percent of the marbles in the jar are green. A number generator should simulates randomly by selecting atleast one of the 60% of green marbles from the jar

5 0

2 years ago

A manager at a local manufacturing company has been monitoring the output of one of the machines used to manufacture chromium sh

denpristay [2]

Answer:

0.682 = 68.2% probability that the average length of these 16 shells will be between 116 and 120 centimeters when the machine is operating "properly".

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with a mean of 118 centimeters and a standard deviation of 8 centimeters.

This means that $\mu = 118, \sigma = 8$

Sample of 16 shells

This means that $n = 16, s = \frac{8}{\sqrt{16}} = 2$

What is the probability that the average length of these 16 shells will be between 116 and 120 centimeters when the machine is operating "properly?"

This is the pvalue of Z when X = 120 subtracted by the pvalue of Z when X = 116.

X = 120

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{120 - 118}{2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.841

X = 116

$Z = \frac{X - \mu}{s}$

$Z = \frac{116 - 118}{2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.159

0.841 - 0.159 = 0.682

0.682 = 68.2% probability that the average length of these 16 shells will be between 116 and 120 centimeters when the machine is operating "properly".

3 0

2 years ago

Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.

kherson [118]

Answer:

A.) (3.6, 0.6)
D.) (2.6, 0.4)

Step-by-step explanation:

See below for a graph.

___

Choices B, C, E can be eliminated on the basis that neither x nor g(x) can be negative. The domain of f(x) is x>0; the range of g(x) is x≥0.

7 0

2 years ago

Peter wants to cut a rectangle of size 6x7 into squares with integer sides. What is the smallest number of squares he can get

Semmy [17]

He can cut 5 squares, by making 1 4 × 4, 2 3 × 3 and 2 2 × 2 squares.

5 0

2 years ago

Azul performed an experiment to determine which crank powered radio works best he crank 15 randomly selected radios of each bran

Setler [38]

50% of X-Treamline Crank Radios are likely to play 30 minutes or longer after 30 cranks, while only 25% of Secure Hike Emergency Radios are likely to play 30 minutes or longer after 30 cranks

8 0

2 years ago

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