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ohaa [14]
2 years ago
7

An online article about an opinion poll says that "41% of Americans own a gun." The poll is based on online survey interviews wi

th 2,700 adults randomly chosen from a numbered list of 750,000 responses from around the United States, excluding New England states.
Part A: What is the population and sample in this poll?

Part B: What type of sampling is used?

Part C: Are there any sources of bias present? Explain.
Mathematics
1 answer:
sergejj [24]2 years ago
3 0

Answer:

See below

Step-by-step explanation:

A) The population of the poll is the United States Population EXCLUDING New England States. In other words, the population is all USA population except the New England population. Remember that population is all the set of individuals from where you extract your sample. The sample are those 2,700 adults interviewed.

B) The sampling used is, as said in the statement, a randome sampling.

C) Yes! There could be a bias because of the exclusion of New England States if the people who lives there tends to have more guns than the average american population. This could be, for example, due to that those states have the least gun owning in America or, contrary, if they have the highest. If Rode Island is the most violent state and has the highest gun owning rate, the results could be biased.  However, we can't confirm it without seeing the data, but there is possible.

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Step-by-step explanation:

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Suppose X is the breaking strength (newtons) of a material, and X is normally distributed with
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Answer:

a) 0.997 is the  probability that the breaking strength is at least 772 newtons.

b) 0.974  is the probability that this material has a breaking strength of at least 772 but not more  than 820    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 800 newtons

Standard Deviation, σ = 10 newtons

We are given that the distribution of  breaking strength is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

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P(x \geq 772)

P( x \geq 772) = P( z \geq \displaystyle\frac{772 - 800}{10}) = P(z \geq -2.8)

= 1 - P(z

Calculation the value from standard normal z table, we have,  

P(x \geq 772) = 1 - 0.003 = 0.997 = 99.7\%

0.997 is the  probability that the breaking strength is at least 772 newtons.

b) P( breaking strength of at least 772 but not more  than 820)

P(772 \leq x \leq 820) = P(\displaystyle\frac{772 - 800}{10} \leq z \leq \displaystyle\frac{820-800}{10}) = P(-2.8 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2.8)\\= 0.977 - 0.003 = 0.974 = 97.4\%

P(772 \leq x \leq 820) = 97.4\\%

0.974  is the probability that this material has a breaking strength of at least 772 but not more  than 820.

7 0
2 years ago
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