Ask question

Ask question

All categories

2 years ago

3

On a coordinate plane, trapezoid K L M N is shown. Point K is at (negative 2, negative 4), point L is at (negative 4, negative 2

), point M is at (negative 2, negative 1), and point N is at (negative 1, negative 2).
In the diagram, KL = 2 StartRoot 2 EndRoot, LM = StartRoot 5 EndRoot, and MN = StartRoot 2 EndRoot. What is the perimeter of isosceles trapezoid KLMN?

StartRoot 2 EndRoot units
StartRoot 5 EndRoot units
3 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units
4 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units

2 answers:

Degger [83]2 years ago

8 0

Answer:

C) $2\sqrt{2} + 2\sqrt{5}$ units

Step-by-step explanation:

it's the third option, i just took the test

perimeter = all the sides lengths added together

Savatey [412]2 years ago

4 0

The perimeter of isosceles trapezoid KLMN is 3√2 + 2√5 units ⇒ 3rd answer

Step-by-step explanation:

The isosceles trapezoid has

Two parallel sides not equal in length called its bases
Two non-parallel sides equal in length

The formula of the slope of a line whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∵ KLMN is an isosceles trapezoid, whose vertices are:

K (-2 , -4) , L (-4 , -2) , M (-2 , -1) , N (-1 , -2)

- Let us find the slopes of its sides to find the parallel sides

∵ $m_{KL}=\frac{-2--4}{-4--2}=\frac{-2+4}{-4+2}=\frac{2}{-2}=-1$

∵ $m_{LM}=\frac{-1--2}{-2--4}=\frac{-1+2}{-2+4}=\frac{1}{2}=0.5$

∵ $m_{MN}=\frac{-2--1}{-1--2}=\frac{-2+1}{-1+2}=\frac{-1}{1}=-1$

∵ $m_{NK}=\frac{-4--2}{-2--1}=\frac{-4+2}{-2+1}=\frac{-2}{-1}=2$

∴ The slope of KL = the slope of MN

∴ KL // MN ⇒ parallel bases

∴ The slope of LM not equal the slope of KN

∴ LM not parallel to KN

∴ LM = KN

∵ The perimeter of the isosceles trapezoid equal the sum of the

parallel bases and the equal sides

∴ The perimeter = KL + LM + MN + NK

∵ KL = 2√2 units , LM = √5 units , MN = √2 units

∵ LM = KN

∴ KN = √5 units

∴ The perimeter = 2√2 + √5 + √2 + √5

∴ The perimeter = 3√2 + 2√5 units

The perimeter of isosceles trapezoid KLMN is 3√2 + 2√5 units

Learn more:

You can learn more about trapezoid in brainly.com/question/7287774

#LearnwithBrainly

You might be interested in

An ostrich can run 6 mph faster than a giraffe. An ostrich can run 7 miles in the same time that a giraffe can run 6 miles. Find

LUCKY_DIMON [66]

NOTE THIS IS AN EXAMPLE:

Let t = time, s = ostrich, and g = giraffe.

Here's what we know:

s = g + 5 (an ostrich is 5 mph faster than a giraffe)

st = 7 (in a certain amount of time, an ostrich runs 7 miles)

gt = 6 (in the same time, a giraffe runs 6 miles)

We have a value for s, so plug it into the first equation:

(g + 5)t = 7

gt = 6

Isolate g so that we can plug that variable value into the equation:

g = 6/t

so that gives us:

(6/t + 5)t = 7

Distribute:

6 + 5t = 7

Subtract 6:

5t = 1

Divide by 5:

t = 1/5 of an hour (or 12 minutes)

Now that we have a value for time, we can plug them into our equations:

1/5 g = 6

multiply by 5:

g = 30 mph

s = 30 + 5

s = 35 mph

Check by imputing into the second equation:

st = 7

35 * 1/5 = 7

7 = 7

5 0

2 years ago

You ask 150 people about their pets. The results show that 9/25 of the people own a dog. Of the people who own a dog. 1/6 of the

asambeis [7]

45 9 x 6 = 54 / 6 = 9. 54 - 9 = 45

6 0

2 years ago

Read 2 more answers

44 students completed some homework and the histogram shows information about the times taken. Work out an estimate of the inter

Vilka [71]

Answer:

q1=11

q3= 33

Step-by-step explanation:

The data set has 44 number of students. The first quartile is 25 % of the numbers in the data set . So

25 % of 44 = 25/100 * 44= 0.25 *44 = 11

So the first quartile lies at 11.

Similarly the third quartile lies at the 75 % of the numbers of the data set . So

75 % of 44 = 75/100 * 44= 0.75 *44 = 33

So the third quartile lies at 33.

5 0

2 years ago

Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.

Lelu [443]

Let's put it this way: If you plot a few non-x-intercept points and then draw a curvy line through them,you will not know if you got the x-intercepts even close to being correct. <span>The only way you can be sure of your x-intercepts is to set the quadratic equal to zero and solve. So its a matter of guessing from the pictures. Basicaly said, the calculator won't give you the exact result.</span>

4 0

2 years ago

Read 2 more answers

A drawer contains 4 capsules numbered 2, 3, 5, and 8. a sample of size 3 is drawn with replacement. what is the standard deviati

Snezhnost [94]

The table below summarises the calculation for the standard deviation of x-bar.

$\begin{tabular}
{|c|c|c|c|}
Drawing (x)&$\bar{x}$&$x-\bar{x}$&$(x-\bar{x})^2\\[1ex]
2,2,2&2&-2.5&6.25\\
2,2,3&2.3&-2.2&4.84\\
2,2,5&3&-1.5&2.25\\
2,2,8&4&-0.5&0.25\\
2,3,3&2.7&-1.8&3.24\\
2,3,5&3.3&-1.2&1.44\\
2,3,8&4.3&-0.2&0.04\\
2,5,5&4&-0.5&0.25\\
2,5,8&5&0.5&0.25\\
2,8,8&6&1.5&2.25\\
3,3,3&3&-1.5&2.25\\
3,3,5&3.7&-0.8&0.64\\
3,3,8&4.7&0.2&0.04\\
3,5,5&4.3&-0.2&0.04\\
3,5,8&5.3&0.8&0.64\\
3,8,8&6.3&1.8&3.24\\
5,5,5&5&0.5&0.25\\
5,5,8&6&1.5&2.25\\
5,8,8&7&2.5&6.25\\
8,8,8&8&3.5&12.25\\
\end{tabular}$

$\sum\bar{x}=89.9 \\ \\ \bar{\bar{x}}= \frac{\sum\bar{x}}{n}=\frac{89.9}{20} \approx4.5 \\ \\ \sum(x-\bar{x})^2=30.41 \\ \\ s.d= \sqrt{ \frac{\sum(x-\bar{x})^2}{n} } = \sqrt{ \frac{30.41}{20} } = \sqrt{1.5205} =1.23$

Therefore, the standard deviation of x-bar is approximately 1.23.

7 0

2 years ago