Answer:
A. f(x) = 6x + 9
Step-by-step explanation:
The given equation is:
y - 6x - 9 = 0
We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.
y - 6x - 9 = 0
y = 6x + 9
f(x) = 6x + 9
Therefore, option A gives the correct answer.
I hope the equation will be 2000=16000(1-r)^t because t is missing in the equation which we need to find.
Given rate: r= 35%= 0.35.
So, first step is to plug in 0.35 for r in the given formula to get the value of t.
Hence, the equation will be:
2000=16000(1-0.35)^t
2000=16000(0.65)^t (By subtraction)
2000/16000= 16000(0.65)^t /16000 (Dividing each sides by 16000)
0.125 = 0.65^t (By simplifying).
log 0.125 = log 0.65^t (Taking log each sides to isolate t).
log 0.125 = t log 0.65 (By applying the log property).
(Dividing each sides by log 0.65)
-0.903/-0.187 =t
t= 4.83
t= 5 ( Rounded to nearest integers)
So, Devon's car is 5 years old.
Water was pumped out in t-hours.
Time t would be the domain, 0 to t.
Answer:
116.82 square inches
Step-by-step explanation:
The overall shape is that of a 10-inch square with four triangles attached. Each of those is an isosceles right triangle with leg lengths of 2.9 inches.
The area of the four triangles is ...
total triangle area = 4(1/2)(2.9 in)(2.9 in) = 16.82 in²
The area of the 10-inch square is ...
square area = (10 in)² = 100 in²
Then the total window area is ...
window area = 16.82 in² +100 in²
window area = 116.82 in²
Answer:
The distance at which the timekeeper is the race car at the start is 50 feet.
Step-by-step explanation:
You know that the car's distance from the timekeeper is represented by
y=293*x +50
where x is time in seconds and y is distance in feet from the timekeeper's position.
You want to determine how far the timekeeper is from the race car at the start. That is, the distance the timekeeper is from the car when the time is equal to zero. This indicates that x = 0. Replacing x by that value in the expression of the distance of the car from the timekeeper as a function of time and solving:
y=293*0 +50
you get:
y=50
<u><em>The distance at which the timekeeper is the race car at the start is 50 feet.</em></u>
