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katrin [286]
2 years ago
3

Which of the following is the best use for the sign chart when graphing rational functions? A) to determine the slope for the gr

aph of F(x)
b)to determine where the zeros are for F(x)
c) to determine if the graph of F(x) is straight or curved
d) to determine where the maximum for the graph is for the graph of F(x)
Mathematics
2 answers:
PSYCHO15rus [73]2 years ago
8 0

The right answer is b) to determine where the zeros are for F(x)


Sign chart is very useful to determine where the function is positive or negative. So, a rational function  must be entirely positive or entirely negative between two consecutive zeros. This means that if you put in order the real zeros of a rational function, they divide the real  number line into intervals in which the function has no sign changes. In other words, if the function is continuous in some interval, then between every change in sign there will be a zero of the rational function.

allochka39001 [22]2 years ago
5 0
The answer is the letter A
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The table shows weights for different US coins. Allen has one of each coin in his hand
Sever21 [200]
Penny- 3g
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2 years ago
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The line 3y+x=25 is a normal to the curve y=x2-5x+k.find the value of constant k.
ladessa [460]

Answer:

k = 11.

Step-by-step explanation:

y = x^2 - 5x + k

dy/dx = 2x - 5 = the slope of the tangent to the curve

The slope of the normal = -1/(2x - 5)

The line  3y + x =25 is normal to the curve so finding its slope:

3y = 25 - x

y = -1/3 x + 25/3 <------- Slope is -1/3

So at the point of intersection with the curve, if the line is normal to the curve:

-1/3 = -1 / (2x - 5)

2x - 5 = 3  giving x = 4.

Substituting for x in y = x^2 - 5x + k:

When x = 4, y =  (4)^2 - 5*4 + k  

y = 16 - 20 + k

so y = k - 4.

From the equation y = -1/3 x + 25/3,  at x = 4

y = (-1/3)*4 + 25/3 = 21/3 = 7.

So y = k - 4 = 7

k = 7 + 4 = 11.

6 0
2 years ago
Multiply the polynomial expressions below.<br> (7x + 5)(2x^3 - 4x^2 + 9x - 3)
LekaFEV [45]

Answer:

14x^8-18x^3+43x^2+24x-15

8 0
2 years ago
Determine the point of intersection between the lines with equations x+3y=5 and 3x−2y=26.
Zolol [24]

Answer:

the ans is :

Step-by-step explanation:

First, it would be helpful to draw a quick sketch of the lines. It helps to visualize the problem.

To find the intersection point, we need to find the point where x and y are the same value in both equations.

The line equations:

6x+2y=26 ................... 1

2x+3y=18 ................... 2

Can be rearranged to the common line equation form: y = mx + c

y = 13 - 3x ................... 3

y = 6 - 2/3 x ................. 4

At the intersection point, y will be equal for both equations. So, we can set 3 equal to 4 and solve for x.

13- 3x = 6 - 2/3 x

13 = 6 + 3x - 2/3x ....... add 3x to both sides

13 = 6 + 2 1/3x ........ simplify

7 = 2 1/3 x ........ subtract 13 from both sides

7 = 7/3 x ......... multiply both sides by 3/7

3 = x

To calculate the y-coordinate substitute x = 3 into 3.

y = 13 - 3x

y = 13 - 3(3)

y = 4

To check your answer, substitute the values for x and y into the other equation, 4.

The point of intersection is (3,4).

If you drew a sketch of the problem, you should be able to see that this point of intersection makes sense.

4 0
2 years ago
Read 2 more answers
PLEASEEEE HELPPP!!!!!
Alecsey [184]
<span>Question 1
Given: m∠H = 30°, m∠J = 50°, m∠P = 50°, m∠N = 100°
To prove that: △HKJ ~ △LNP
Statement                                                                              Reason

1. m∠H = 30°, m∠J = 50°, m∠P = 50°, m∠N = 100°   1. given
2. m∠H + m∠J + m∠K = 180°                                      2. ?
3. 30° + 50° + m∠K = 180°                                          3. substitution property
4. 80° + m∠K = 180°                                                    4. addition
5. m∠K = 100°                                                              5. subtraction property of equality
6. m∠J = m∠P; m∠K = m∠N                                        6. substitution
7. ∠J ≅ ∠P; ∠K ≅ ∠N                                                   7. if angles are equal then they are congruent
8. △HKJ ~ △LNP                                                        8. AA similarity theorem

The reason that is missing in step 2 is triangle angle sum theorem.
</span>The triangle angle sum theorem states that t<span>he sum of the measures of the interior angles of a triangle is 180°.

</span>Question 2
<span>Given that △ABC is an isosceles triangle with legs AB and AC and △AYX is also an isosceles triangle with legs AY and AX.

To prove that △ABC ~ △AYX.
Statements                                                               Reasons
1. △ABC is isosceles with legs AB and AC;
△AYX is also isosceles with legs AY and AX.         1. given
2. AB ≅ AC and AY ≅ AX                                        2. definition of isosceles triangle
3. AB = AC and AY = AX                                         3. definition of congruency
4. AY • AC = AX • AC                                              4. multiplication property of equality
5. AY • AC = AX • AB                                              5. substitution property of equality
6. AY </span><span>• AC / AB = AX                                              6. division property of equality
7. AY/AB = AX/AC                                                  7. division property of equality
</span><span>8. ?                                                                          8. ?
9. △ABC ~ △AYX                                                   9. SAS similarity theorem

 The statement and reason missing in the proof are ∠A ≅ ∠A; reflexive property</span>
<span>SAS Similarity or Side-Angle-Side similarity states that when two triangles have corresponding angles that are congruent and corresponding sides with identical ratios, then the triangles are similar.</span>

<span>Question 3 -
Given that line RS intersects triangle BCD at two points and is parallel to segment DC.
The statements thet are correct is △BCD is similar to △BSR.</span>
6 0
2 years ago
Read 2 more answers
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