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LenKa [72]
2 years ago
11

A group of campers is going to occupy 3 campsites at a campground. There are 17 campsites from which to choose. In how many ways

can the campsites be chosen?
Mathematics
1 answer:
Alexeev081 [22]2 years ago
5 0

Answer:

Campsites be chosen in 680 ways.

Step-by-step explanation:

Given:

Number of  campsites= 17

Number of campsites that are to be occupied=3

To Find:

Number of ways can the campsites be chosen=?

Solution:

Combination:

In mathematics, a combination is a way of selecting items from a collection where the order of selection does not matter. Suppose we have a set of three numbers P, Q and R. Then in how many ways we can select two numbers from each set, is defined by combination.

nCr = n(n - 1)(n - 2) ... (n - r + 1)/r! = n! / r!(n - r)!

No of ways in which campsites can be chosen= \frac{17!}{3!(17-3)!}17C3

=>\frac{17!}{3!(14!)}

=>\frac{15\times16\times17}{3\times 2\times 1}

=>\frac{4080}{6}

=>680

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Alexxx [7]

Answer:

(-4)(-4)(-4)(p)(p)(p)(p)

Step-by-step explanation:

= (-4)^3 * p^4

The expanded form of it is:

= (-4)(-4)(-4)(p)(p)(p)(p)

4 0
2 years ago
Read 2 more answers
An ant begins at the top of the pictured octahedron. If the ant takes two "steps", what is the probability it ends up at the bot
Aleksandr-060686 [28]

Answer:

P_{bottom}=\frac{1}{4}=0.25

Step-by-step explanation:

Starting from the top, the ant can only take four different directions, all of them going down, every direction has a probability of 1/4. For the second step, regardless of what direction the ant walked, it has 4 directions: going back (or up), to the sides (left or right) and down. If the probability of the first step is 1/4 for each direction and once the ant has moved one step, there are 4 directions with the same probability (1/4  again), the probability of taking a specific path is the multiplication of the probability of these two steps:

P_{2steps}=\frac{1}{4}*\frac{1}{4}=\frac{1}{16}

There are only 4 roads that can take the ant to the bottom in 2 steps, each road with a probability of 1/16, adding the probability of these 4 roads:

P_{bottom}=\frac{1}{16}+\frac{1}{16}+\frac{1}{16}+\frac{1}{16}=\frac{4}{16}=\frac{1}{4}

The probability of the ant ending up at the bottom is \frac{1}{4} or 0.25.

6 0
2 years ago
In the diagram, transversal t cuts across the parallel lines a and b. Match the pairs of angles with the relationship that shows
charle [14.2K]

we know that

<u>case a)</u> alternate exterior angles

m∠2=m∠7 --------> by alternate exterior angles

m∠1=m∠8 --------> by alternate exterior angles

<u>case b)</u> alternate interior angles

m∠3=m∠6 --------> by alternate interior angles

m∠5=m∠4 --------> by alternate interior angles

<u>case c)</u> corresponding angles

m∠1=m∠5 --------> by corresponding angles

m∠3=m∠7 --------> by corresponding angles

m∠2=m∠6 --------> by corresponding angles

m∠4=m∠8 --------> by corresponding angles

<u>case d)</u> vertical angles

m∠1=m∠4 --------> by vertical angles

m∠2=m∠3 --------> by vertical angles

m∠5=m∠8 --------> by vertical angles

m∠6=m∠7 --------> by vertical angles

therefore

the answer in the attached figure

5 0
2 years ago
Lois says any addition equation where the addends are all the same can be written as a multiplication equation. Is Lois correct
USPshnik [31]
Lois is correct. This is because multiplication is repeated addition. It means that when your addends are just the same number but added several times, the sum is just equivalent to the product of that number times the number of times it was added. For example, 4+4+4 = 4×3 = 12.
6 0
2 years ago
The probability that a person in the United States has type B​+ blood is 12​%. Three unrelated people in the United States are s
V125BC [204]

Answer:

The probability that all three have type B​+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a person in the United States has type B​+ blood is 12​%.

This means that p = 0.12

Three unrelated people in the United States are selected at random.

This means that n = 3

Find the probability that all three have type B​+ blood.

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728

The probability that all three have type B​+ blood is 0.001728

4 0
2 years ago
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