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Radda [10]
2 years ago
13

Lois says any addition equation where the addends are all the same can be written as a multiplication equation. Is Lois correct

or not and why
Mathematics
1 answer:
USPshnik [31]2 years ago
6 0
Lois is correct. This is because multiplication is repeated addition. It means that when your addends are just the same number but added several times, the sum is just equivalent to the product of that number times the number of times it was added. For example, 4+4+4 = 4×3 = 12.
You might be interested in
Using the extended Euclidean algorithm, find the multiplicative inverse of a. 135 mod 61 b. 7465 mod 2464 c. 42828 mod 6407
rodikova [14]

Answer:

(a)1≡47 mod 61

(b)1≡2329 mod 2464

(c)Does not exist

Step-by-step explanation:

The operation a(mod b) has an inverse if the the two integers (a,b)

are co-prime. i.e. their g.c.d is 1.

(a)Given 135 mod 61

We first reduce it to its lowest form.

135 mod 61=13 mod 61

61=13(4)+9 ==> 9=61-13(4)

13=9(1)+4 ==> 4=13-9(1)

9=4(2)+1 ==> 1=9-4(2)

4=1(4)

Next we rewrite 1 as a linear combination of 13 and 61.

1=9-4(2)

=9-(13-9(1))2

=9(3)-13(2)

=(61-13(4))(3)-13(2)

=61(3)-13(12)-13(2)

1=61(3)-13(14)

1=61(3)+13(-14)

1≡-14 mod 61≡(-14+61)mod 61

1≡47 mod 61

(b)7465 mod 2464

Reducing it to its lowest form

7465 mod 2464=73 mod 2464

2464=73(33)+55 ==>55=2464-73(33)

73= 55(1)+18 ==> 18=73-55(1)

55=18(3)+1 ==>1=55-18(3)

18=1(18)

Rewriting 1 as a linear combination of 73 and 2464.

1=55-18(3)

=2464-73(33)-(73-55(1))(3)

=2464-73(33)-73(3)+55(3)

=2464-73(36)+55(3)

=2464-73(36)+(2464-73(33))(3)

=2464-73(36)+2464(3)-73(99)

=2464(4)-73(135)

1=2464(4)+73(-135)

Therefore:

1≡-135 mod 2464

1≡(-135+2464)mod 2464

1≡2329 mod 2464

(c)42828 mod 6407

The two numbers are not co-prime. In fact their g.c.d is 43.

Therefore their inverse does not exist.

4 0
2 years ago
Read 2 more answers
A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of
notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

M = z\frac{\sigma}{\sqrt{n}}

0.0001 = 2.327\frac{0.0003}{\sqrt{n}}

0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

n = 48.73

Rounding up

49 measurements are needed.

7 0
1 year ago
Lisa the numbers least to greatest -2/5 -2.47 -2 1/2 5 21/4
Paraphin [41]

Answer:

least to greatest are:

-2.5, -2.47, -2/5, 5, 21/4

3 0
1 year ago
The scale for the drawing of a rectangular playing field is 2 inches= 5 feet. Write an equation you can use to find the dimensio
iris [78.8K]

Answer:

Step-by-step explanation:

Given:

Scale

2 inches : 5 feet

Actual dimensions

Let x be the dimension of the scale drawing (in inches) and y, the corresponding dimension of the actual field (in feet).

Scaled dimension = scale × actual dimension

Actual dimension, x = y × 5 ft/2 in

2 × x = 5 × y

Equation:

2x = 5y

3 0
1 year ago
What is the equation for g, which is f(x) = 2x2 + 3x − 1 reflected across the y-axis? Group of answer choices g(x) = −2x2 − 3x −
Sergio [31]

Answer:

g(x) = 2x^2 - 3x - 1

Step-by-step explanation:

Given

f(x) = 2x^2 + 3x - 1

Required

Determine g(x), if f(x) is reflected across the y axis

<em>When a function (x,y) is reflected across the y axis, the new function becomes (−x,y).</em>

<em />

In other words,

g(x) =  f(-x)

Calculating f(-x)

f(-x) = 2(-x)^2 + 3(-x) - 1

f(-x) = 2x^2 - 3x - 1

Substitute g(x) for f(-x)

g(x) = 2x^2 - 3x - 1

<em>Hence;</em>

g(x) = 2x^2 - 3x - 1

7 0
1 year ago
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