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Sidana [21]
2 years ago
13

????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered

at the origin with radius 44 and central angle ????/3π/3. Use Green's theorem to calculate the circulation of ????⃗ F→ around ????C.
Mathematics
1 answer:
Karolina [17]2 years ago
6 0

By Green's theorem, the integral of \vec F along C is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy

which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3

so that the value of the integral is

\dfrac{6\times8\pi}3=\boxed{16\pi}

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kari74 [83]
When a point divides a line segment into ratios of k1:k2, the formula to find the coordiates of the point is:
x=(k2*x1+k1*x2)/(k1+k2), y=(k2*y1+k1*y2)/(k1+k2), 
(x1,y1) being the coordinates of the starting point, and (x2,y2) coordinates of the end point. 
in this case, 3.6=[2*(-6)+3x2]/5
-12+3x2=18
3x2=30
x2=10

use the same method to find y2: -0.4=(2*5+3y2)/5
3y2=-12
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so the the coordinates of B is (10,-4)

use the same method to find the coordinates of D.

the answer I've got for D is (58/9, -2) please double check my calculation.
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2 years ago
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How much would Carol have to invest today at 6.2% compounded annually to have $4600 for a vacation to China in two years?
KiRa [710]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
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P=\textit{original amount deposited}\\
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n=
\begin{array}{llll}
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t=years\to &2
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Step-by-step explanation:

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The equation of a line passing through two points is given by :

y-y_1=m(x-x_1)\ \text{m is slope}\\\\y-5=\dfrac{y_2-y_1}{x_2-x_1}(x-8)\\\\y-5=\dfrac{-9-5}{-12-8}\times (x-8)\\\\y-5=\dfrac{7}{10}\times (x-8)\\\\10y-50=7x-56

or

-50+56=7x-10y\\\\7x-10y=6

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0,3 - 3,0

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