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Sidana [21]
2 years ago
13

????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered

at the origin with radius 44 and central angle ????/3π/3. Use Green's theorem to calculate the circulation of ????⃗ F→ around ????C.
Mathematics
1 answer:
Karolina [17]2 years ago
6 0

By Green's theorem, the integral of \vec F along C is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy

which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3

so that the value of the integral is

\dfrac{6\times8\pi}3=\boxed{16\pi}

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A freezer has a temperature of 14 degrees Fahrenheit. An ice-cube tray full of water is placed in the freezer. The function f(t)
Hitman42 [59]

Answer:

  65

Step-by-step explanation:

You can use f(15) = 40 to solve for C, then find f(0), the initial temperature.

  40 = f(15)

  40 = Ce^(-0.045·15) +14 = .50916C +14

  26 = .50916C

  26/.50916 = C ≈ 51.065

Then f(0) is ...

  f(0) = 51.065·e^0 +14 = 65.065 ≈ 65

The initial temperature of the water was 65 degrees Fahrenheit.

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2 years ago
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A container holds 2,000 g of water. This is the same as:
liraira [26]
1 g = 1 cm^3 = 1 mL. Hence, 2000 g = 2000 cm^3 = 2000 mL.
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1 year ago
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A person is standing exactly 36 ft from a telephone pole. There is a 30° angle of elevation from the ground to the top of the po
nika2105 [10]

Answer:

20.78feet

Step-by-step explanation:

The question made us to understand that the man is standing and also there is angle of elevation, then we need to draw a right triangle having a base equal to 36 feet with an angle from the base to the top of the pole which is 30 degrees.

tan= opposite side / adjacent side

Let height of the pole =h

Tan(30)= h/36

But tan 30degree= 1/√3

h= 36 × 1/√3

h= 20.78feet

Therefore, the height of the pole= 20.78feet

CHECK THE ATTACHMENT FOR DETAILED FIGURE

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in a scale drawing of an apartment, 1 centimeter represents 2 3/4 feet. If the length of the kitchen in 4 1/2 cm on the scale dr
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It is 12.375 feet long.

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According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1
JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means p=0.10 and q=1-0.10=0.90.

If 1100 Americans are sampled, then the sample size is n=1100 .

The mean of the distribution is \mu=np.

This means \mu=1100\times 0.10=110

The standard deviation is \sigma=\sqrt{npq}

We substitute the values to get:

\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)

We now convert to Z-scores to get:

P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)

We convert to z-scores:

P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48

From the normal distribution, P(z>164.5)=0

c)  First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\le88)=P(X\:

We convert to z-scores:

P(X\:

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

3 0
2 years ago
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