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Alborosie
2 years ago
8

You went on three hikes. On each hike, you saw a different number of animals: Hike Length of hike (\text{km})(km)left parenthesi

s, start text, k, m, end text, right parenthesis Number of animals seen Rivers Edge 3 8 Wooded Marsh 8 20 Canyon Creek 15 35 Order your hikes by number of animals seen per kilometer from least to greatest
Mathematics
2 answers:
HACTEHA [7]2 years ago
8 0

Answer:

Canyon Creek - Wooded Marsh - Rivers Edge

Step-by-step explanation:

The hiker saw 8 animals in 3 km in Rivers Edge, that makes 8/3 = 2.67 animals per kilometer.

The hiker saw 20 animals in 8 km in Wooded Marsh, that makes 20/8 = 2.5 animals per kilometer.

The hiker saw 35 animals in 15 km in Canyon Creek, that makes 35/15 = 2.33 animals per kilometer.

kherson [118]2 years ago
3 0

Answer:

Step-by-step explanation:

First you will multiply Rivers edge 3x8=24 and then wooden marsh 8x20=160, lastly canyon creek 15x35=525. So it would be canyon creek, wooden marsh and rivers edge!

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18 x 10 = 180

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2 years ago
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2 years ago
"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r
sergiy2304 [10]

Answer:

(a) Null Hypothesis, H_0 : p_1-p_2=0  or  p_1= p_2  

    Alternate Hypothesis, H_A : p_1-p_2\neq 0  or  p_1\neq p_2

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

<em />

<em>Let </em>p_1<em> = proportion of drivers that were in compliance initially</em>

p_2<em> = proportion of drivers that were in compliance one year later</em>

(a) <u>Null Hypothesis</u>, H_0 : p_1-p_2=0  or  p_1= p_2      {means that there is not any statistical difference in these two proportions measured initially and then one year later}

<u>Alternate Hypothesis</u>, H_A : p_1-p_2\neq 0  or  p_1\neq p_2     {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is <u>Two-sample z proportion statistics</u>;

                     T.S.  = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers in compliance initially = 98.9%

\hat p_2 = sample proportion of drivers in compliance one year later = 96.9%

n_1 = sample of drivers initially = 1,250

n_2 = sample of drivers one year later = 1,100

(b) So, <u><em>the test statistics</em></u>  =  \frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }  

                                           =  3.33

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 3.33) = 1 - P(Z \leq 3.33)

                                            = 1 - 0.99957 = <u>0.00043</u>

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis.</em></u>

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

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Answer: $ 14

Step-by-step explanation:

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Thus, the original price of one pair of socks = $ 9

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Hence, the total change = original price of socks - the price of socks in the sale = 54 - 40 =  $ 14

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2 years ago
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