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1 year ago

Brian is choosing an appetizer, an entrée, and a drink. If he

Mathematics

2 answers:

Jet001 [13]1 year ago

7 0

Answer:

Total number of possible outcomes = 27

Number of favorable outcomes = 1

Probability = 1/27

Step-by-step explanation:

galben [10]1 year ago

5 0

Answer:

The first question is right :) :) :)

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A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll

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1 year ago

Jayla buys and sells vintage clothing. She bought two blouses for $25.00 each and later sold them for $38.00 each. She bought th

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1 year ago

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If mc022-1.j pg and mc022-2.j pg, what is the value of (f – g)(144)? –84 –60 0 48

Mashutka [201]

Answer:

Step-by-step explanation:

f(x) = √(x) + 12

g(x) = 2√(x)

(f-g)(x) = √(x) + 12 - 2√(x)

(f-g)(x) = 12 - √(x)

if x = 144

(f-g)(144) = 12 - √(144) = 12 - 12 = 0

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2 years ago

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Gino has a stick of pepperoni that is 26 1/2 inches long. He wants to cut 1/2 inch pieces to put on his large pizza. How many pi

ikadub [295]

Answer:57 pieces

Step-by-step explanation:

If the pepperoni is 26 1/2 inches long and he is cutting then 1/2 in slices. You are going to get 2 slices per inch. So multiply 26 x 2 which is 56 then add 1 for the half inch which gives you 57 slices

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2 years ago

A row of tiny red beads is placed at the beginning and at the end of a 20‐centimeter bookmark.

AlladinOne [14]

Answer:

51 rows

Step-by-step explanation:

Given

Length of bookmark = 20cm

Distance between beads = 4mm

Required

Number of rows of beads

First, the distance between the rows of beads must be converted to cm

if 1mm = 0.1cm

then

4mm = 4*0.1cm

4mm = 0.4 cm

This means that each row of beads is placed at 0.4 cm mark.

The distance between each row follows an arithmetic progression and it can be solved as follows;

$T_n = a + (n-1)d$

Where $Tn = 20cm$ (The last term)

$a = 0 cm$ (The first term)

$d = 0.4cm$ (The distance between each row of beads)

n = ?? (number of rows)

Solving for n; we have the following;

$T_n = a + (n-1)d$ becomes

$20 = 0 + (n-1)0.4$

$20 = (n-1)0.4$

DIvide both sides by 0.4

$\frac{20}{0.4} = \frac{(n-1)0.4}{0.4}$

$50 = (n-1)$

$50 = n-1$

Add 1 to both sides

$50 + 1= n-1 + 1$

$n = 51$

Hence, the number of rows of beads is 51

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1 year ago