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Illusion [34]
2 years ago
13

Consider a process in which the entropy of a system increases by 125 J K−1 and the entropy of the surroundings decreases by 125

J K−1. Is the process spontaneous?
Chemistry
1 answer:
expeople1 [14]2 years ago
4 0

Answer : The process is not spontaneous.

Explanation :

As, we know that:

Change in entropy = Change in entropy of system + Change in entropy of surrounding

As we are given in question, the entropy of surroundings decrease by the same amount as the entropy of the system increases.

For the given reaction to be spontaneous, the total change in entropy should be positive.

Given :

Entropy change of system = +125J/K

Entropy change of surroundings = -125J/K

Total change in entropy = Entropy change of system + Entropy change of surroundings

Total change in entropy = 125 J/K + (-125 J/K)

Total change in entropy = 0

The process is at equilibrium because the entropy change is equal to zero. So, the process is not spontaneous.

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A. A nurse practitioner prepares 500. mL of an IV of normal saline solution to be delivered at a rate of 80. mL/h. What is the i
nydimaria [60]
A. Quantity of saline = 500mL 
Rate of infusion = 80 mL / h 
Infusion time = Quantity / Rate = 500 mL / (80 mL/hr) = 6.25 hr 
b. Child weight = 72.6 lb = 32.93 kg 
Medrol to be given = 1.5 mg per kg 
Quantity of Medrol = 20 mg/mL 
Dosage available = 20 mg/mL / 1.5 mg/kg = 13.33 kg/mL 
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8 0
2 years ago
When 50 ml (50 g) of 1.00 m hcl at 22oc is added to 50 ml (50 g) of 1.00 m naoh at 22oc in a coffee cup calorimeter, the tempera
vitfil [10]

Answer:

\boxed{\text{2700 J}}

Explanation:

HCl + NaOH ⟶ NaCl + H₂O

There are two energy flows in this reaction.  

Heat of reaction + heat to warm water = 0  

           q₁             +              q₂                 = 0  

           q₁             +          mCΔT              = 0  

Data:

    m(HCl) = 50 g

m(NaOH) = 50 g

           T₁ = 22       °C

          T₂ = 28.87 °C

           C = 4.18 J·°C⁻¹g⁻¹

Calculations:

 m = 50 + 50 = 100 g

ΔT = 28.87 – 22 = 6.9 °C

 q₂ = 100 × 4.18 × 6.9 = 2900 J

q₁ + 2900 = 0

q₁ = -2900 J

The negative sign tells us that the reaction produced heat.

The reaction produced \boxed{\textbf{2900 J}}.

7 0
2 years ago
Several amino acids are intermediates of the urea cycle, having side ammonia groups that join with free carbon dioxide (CO2) and
mr_godi [17]

Answer:

A. Arginine

Explanation:

The urea cycle is the cycle of the biochemical reactions which produces urea from ammonia.

Steps of the urea cycle:

  • Carbamoyl phosphate, in presence of ornithine transcarbamoylase is converted to citrulline by the denotation of carbamoyl phosphate groupto ornithine and a phosphate group is released.
  • Amino group of the aspartate and carbonyl group of the citrulline are condensed to form argininosuccinate in the presence of enzyme, argininosuccinate synthetase. This condensation reaction is ATP dependent.
  • <u>Argininosuccinate then undergoes cleavage by the argininosuccinase to form intermediate, arginine and fumarate.</u>
  • <u>Arginine is then cleaved by the arginase to form urea as well as ornithine.</u> Ornithine is transported back to mitochondria to begin urea cycle again.
7 0
2 years ago
Which statement best describes the atoms of the gas neon? O They slide past each other. They move freely in all directions. O. T
timofeeve [1]

Answer:

The statement that describes the gas of neon is

1. They are far apart.

2. They move constantly.

3. They move freely in all directions.

4. They move at high speed. Neon is termed as a chemical element. It is a noble gas.

It is odorless, colorless, inert monatomic gas when under standard condition. Neon is the second of the rare gases to be discovered. The second lightest inert gas.

Explanation:i just know oki

7 0
2 years ago
Read 2 more answers
C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Andreas93 [3]

Answer :

Ethanol (C_2H_5OH) act as reducing agent.

The smallest possible integer coefficient of MnO_4^- in the combined balanced equation is, 4

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

The oxidation-reduction half reaction will be :

Oxidation : C_2H_6O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}

  • Now balance oxygen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • Now balance hydrogen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

Reduction : MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O

  • Now balance the charge.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

Reduction : MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In order to balance the electrons, we multiply the oxidation reaction by 5 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 5C_2H_6O+5H_2O\rightarrow 5C_2H_4O_2+20H^++20e^-

Reduction : 4MnO_4^-+32H^++20e^-\rightarrow 4Mn^{2+}+16H_2O

The balanced chemical equation in acidic medium will be,

5C_2H_6O+4MnO_4^-+12H^+\rightarrow 5C_2H_4O_2+4Mn^{2+}+11H_2O

In the redox reaction ethanol act as reducing agent and permanganate ion act as an oxidizing agent.

4 0
2 years ago
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