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2 years ago

What is the additive inverse of the complex number -12+4i?

Mathematics

2 answers:

Serga [27]2 years ago

6 0

<em>The additive inverse of the complex number -12+4i is 12-4i</em>

<h2>Explanation:</h2>

The standard form of complex numbers is given by:

$a+bi \\ \\ Where: \\ \\ a,b:Real \ numbers \\ \\ i:imaginary \ number$

In this case we have:

$-12+4i$

The Additive inverse of a complex number is another complex number such that the sum of it and the original one yields 0. In other words:

$s+(-s)=0 \\ \\ Being \ s \ and \ -s \ complex \ numbers$

So, in this case we can write:

$s=-12+4i \\ \\ \\ So: \\ \\ -s=12-4i \\ \\ \\ Because: \\ \\ (-12+4i)+(12-4i)=0$

Finally, <em>the additive inverse of the complex number -12+4i is 12-4i</em>

<h2>Learn more:</h2>

Complex numbers: brainly.com/question/10609227

#LearnWithBrainly

levacccp [35]2 years ago

3 0

additive inverse of the complex number -12+4i is 12-4i

Step-by-step explanation:

We need to find the additive inverse of the complex number -12+4i

The complex number given is -12+4i

The additive inverse is:

For finding additive inverse, we change the signs of both terms.

The sum of number and its additive inverse is always zero.

Additive inverse = 12-4i

So, additive inverse of the complex number -12+4i is 12-4i

Keywords: Solving Complex numbers

Learn more about Complex numbers at:

#learnwithBrainly

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