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2 years ago

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Keith mows lawns in his neighborhood. He charges a base rate of $15 per lawn and then charges $5 per hour, h, it takes him to mo

w the lawn. Keith wants to make more than $100 today. Which inequality below represents the situation?

1 answer:

Bogdan [553]2 years ago

7 0

Answer:

y * ((h * x) + 15)

Step-by-step explanation:

l (Lawns)

h = hours

x = number of hours

y = number of lawns

y * ((h * x) + 15)

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let x = the amoun of raw sugar in tons a procesing plant is a sugar refinery process in one day . suppose x can be model as expo

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Answer:

The answer is below

Step-by-step explanation:

A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?

Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

$f(x)=\lambda e^{-\lambda x}\\But\ \lambda= 1/\mu=1/4 = 0.25\\Therefore:\\f(x)=0.25e^{-0.25x}\\$

a) P(x > 5) = $\int\limits^\infty_5 {f(x)} \, dx =\int\limits^\infty_5 {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_5=e^{-1.25}=0.2865$

b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.

That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757

c) Let b be the amount of raw sugar should be stocked for the plant each day.

P(x > a) = $\int\limits^\infty_a {f(x)} \, dx =\int\limits^\infty_a {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_a=e^{-0.25a}$

But P(x > a) = 0.05

Therefore:

$e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98$

a ≅ 12

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2 years ago

A recipe that makes 4 servings calls for Two-thirds cup of flour. How much flour is required to make 20 servings? 6 cups 3 and o

Vlad [161]

Answer:

3 1/3 cups of flour

Step-by-step explanation:

20/4 = 5

20 servings is 5 times 4 servings, so you need 5 times the amount of ingredients.

5 * 2/3 = 10/3 = 3 1/3

Answer: 3 1/3 cups of flour

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2 years ago

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jonathan ran 5 days this week. the most he ran in one day was 3.5 miles. write an inequality that shows the distance jonathan co

poizon [28]

Let m represent the number of miles this guy runs in a day.
He runs every day, so the minimum number of miles has to be greater than 0.
According to the problem statement, the max number of miles is 3.5 miles or less.

Translate this into a (symbolic) inequality.

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2 years ago

The ratio of the areas of two similar parallelogram is 4:9. Find the height of the bigger one if the smaller is if height 4cm

N76 [4]

Answer:

look it up because found the correct answer there

Step-by-step explanation:

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2 years ago

When expressing sets, you may write "inf" for infinity and "U" for union.

GarryVolchara [31]

Answer:

The complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

Step-by-step explanation:

The given set in interval notation is

(−5,6]

It means the set is defined as

$A=\{x|x\in R,-5$

If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.

Here, universal set is R, the set set of all real numbers.

$U=\{x|x\in R\}$

The complement of the given set is

$A^c=U-A$

$A^c=\{x|x\in R,-\infty$

Complement of the given set in interval notation is

$A^c=(-\infty,-5]\cup(6,\infty)$

Therefore the complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

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2 years ago