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sergij07 [2.7K]
2 years ago
7

Last week Jack worked 70 hours and earned $ 1,260. If he earned his regular hourly wage for the first 40 hours worked, 3/2 times

his regular hourly wage for the next 20 hours worked, and 2 times his regular hourly wage for the remaining 10 hours worked, what was his regular hourly wage?
Mathematics
1 answer:
lisabon 2012 [21]2 years ago
4 0

Answer:

regular hourly wage is $14 per hour

Step-by-step explanation:

Let  x be the regular hourly wage

he earned his regular hourly wage for the first 40 hours worked

so its 40x

3/2 times his regular hourly wage for the next 20 hours worked

3/2 is 1.5. 1.5x for next 20 hours

So its 30x

2 times his regular hourly wage for the remaining 10 hours worked

2x times 10 is 20x

Now we add all the wages we got . total earned is 1260

40x+30x+20x=1260

90x=1260

divide both sides by 90

x= 14

So regular hourly wage is $14 per hour

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A statistics teacher was interested in the relationship between the number of days students waited to start a project and the sc
Fiesta28 [93]

Answer:

<em>A: For each increase in the number of procrastination days by 1, the predicted grade decreases by 3.64 points.</em>

Step-by-step explanation:

<u>The slope of a Regression Line</u>

A straight line can be represented in the slope-intercept form:

y = mx + b

Where m is the slope and b is the y-intercept.

The slope describes how fast and in what direction the graph goes when x changes values.

If m is positive, increments in x imply increments in y.

If m is negative, increments in x imply decrements in y.

The regression line is:

ŷ = –3.64x + 96.5

Where:

x = the number of procrastination days

ŷ = the predicted grade

We can say the slope is m=-3.64. This means that:

A: For each increase in the number of procrastination days by 1, the predicted grade decreases by 3.64 points.

5 0
2 years ago
Read 2 more answers
Which expression(s) have a greatest common factor (GCF) of 3xy2 with 42xy4
Aleks [24]

Answer:

3xy2

Step-by-step explanation:

GCF is the largest  factors which are common in two or more numbers.

We find the GCF of two or more number number by breaking each number into their factor and then observe which factors are common in the group and then we multiple the common number to get the GCF.

Lets understand this by an example

GCF of 24 and 36

factors of 12 = 2*2*2*3  ,   factors of 36 = 2*2*3*3

hence we see that 2,2 and 3 are common in 12 and 36 hence

GCF will be 2*2*3 = 12

Coming back to problem

given

Expression 1 is 3xy^2

factor of 3xy^2 = 3*x*y*y

Expression 2 is 42xy4

factor of 42xy4 = 2*3*7*x*y*y*y*y

common factor between the two expressions are

3, x, y , y

hence GCF will be = 3*x*y*y =3xy2  Answer

3 0
2 years ago
If the number of equally likely sample outcomes of a single stage of an experiment is 4, what is the total number of elements in
Svetradugi [14.3K]

Answer:

The total number of elements in the sample space if the experiment has 3 stages is 64 ....

Step-by-step explanation:

The answer is C.

According to the given statement the number of equally likely sample outcomes of a single stage of an experiment is 4

To find the total number of elements in the sample space if the experiment has 3 stages, we just simply multiply 4 three times.

4³ = 4*4*4

= 64

Therefore  the total number of elements in the sample space if the experiment has 3 stages is 64 ....

6 0
2 years ago
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Given line has the equation 2X +12 Y equals negative one what is the equation in slope intercept form of the line that is perpen
Flauer [41]

Answer:

y = 12x + 9 is the answer.

Step-by-step explanation:

Since the given equation is 2x + 12 y = -1

12y = -2x -1

y=-\frac{1}{12}(2x+1)

y=-\frac{1}{12}x-\frac{1}{12}

Now this line is in the form of y = mx + c

Here m = slope = -1/12

We have to calculate the slope of another line perpendicular to this line and passing through (0, 9).

Let the equation is y = m' + c'

We know m×m' = -1 for two perpendicular lines

-(\frac{1}{12})(m')=-1

m' = 12

Therefore the equation will be

y = 12x + c'

Since this line passes through ( 0, 9)

9 = 12×0 + c'

c' = 9

Now the equation will be

y = 12x + 9

This is the answer.

3 0
2 years ago
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Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
2 years ago
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