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Dominik [7]
2 years ago
13

Scores on a biology final exam are normally distributed with a mean of 220 and a standard deviation of 16. Determine the percent

age of samples of size 4 that will have mean scores within 12 points of the population mean score of 220. Round your answer to two decimal places.
Mathematics
1 answer:
IrinaK [193]2 years ago
6 0

Answer:

86.64%

Step-by-step explanation:

Mean (μ) = 220

σ= 16

n= 4

mean score(X) = 220 -12

= 208

Using central limit theorem which says that for a sample of size (n), the standard error is

standard deviation /√n

= 16/√4

= 16/2

= 8

Standard error = 8

Using Z score

Z = (μ - x) / standard error

Z= (220 -208)/8

Z= 12/8

Z= 1.5

From the table, Z = 1.5 = 0.4332

Since the normal distribution curve is symmetrical, we have

0.4332*2

= 0.8664

Percentage = 0.8664*100

= 86.64%

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Theres 12 possibilities and she has 3 numbers which means each number has a 1 out of 12 chance of winning the prize. Molly has three numbers so she has a probability of 3/12 to win a prize.

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The sum of 23.8 and a number is 28.17, as shown below. What number should go in the box to complete the addition problem?
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Elis [28]

Answer:

5th grade mean - 4.67

7th grade mean - 3.46

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If 5 years ago nina was twice as old as sam, how soon from now will she be 1.5 times as old as sam? if x is sam's age 5 years ag
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7 0
2 years ago
Use the binomial theorem to find the coefficient of xayb in the expansion of (5x2 + 2y3)6, where a) a = 6, b = 9. b) a = 2, b = 15.
goldfiish [28.3K]

Answer:

Step-by-step explanation:

                    1

                1      1

            1      2      1

         1     3      3      1

      1    4     6       4       1

   1   5    10     10       5     1

 1    6   15   20      15    6     1

1    6   15   20      15    6     1

we use these for the expansion of (5x² + 2y³)⁶

1(5x²)⁶(2y³)⁰ + 6(5x²)⁵(2y³)¹ + 15(5x²)⁴(2y³)² + 20(5x²)³(2y³)³+  15(5x²)²(2y³)⁴+ 6(5x²)¹(2y³)⁵ + 1(5x²)⁰(2y³)⁶

78125ₓ¹²+187500ₓ¹⁰ y³ +37500ₓ⁸y⁶+20000ₓ⁶y⁹+6000x⁴y¹²+960x²y¹⁵+2y¹⁸

a.)a = 6, b = 9. the coefficient of xᵃyᵇ ( 20000ₓ⁶y⁹) = 20000

b) a = 2, b = 15. the coefficient of xᵃyᵇ ( 960x²y¹⁵) = 960

c) a = 3, b = 12. the coefficient of xᵃyᵇ is not present

d) a = 12, b = 0 the coefficient of xᵃyᵇ ( 78125ₓ¹²)  = 78125

e) a = 8, b = 9. the coefficient of xᵃyᵇ is not present

7 0
2 years ago
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