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Alex
2 years ago
7

Shaun drew ΔLMN, in which m∠LMN = 90°. He then drew ΔPQR, which was a dilation of ΔLMN by a scale factor of 3 from the center of

dilation at point M. Which of these can be used to prove ΔLMN ~ ΔPQR by the AA similarity postulate?
Mathematics
1 answer:
Tatiana [17]2 years ago
4 0

Answer:

Step-by-step explanation:

we have ΔLMN as our parent triangle, where M=90°. Another triangle ΔPQR is formed which was dilation of ΔLMN with a factor of one and half that is 1.5

We are also given that the center of dilation is M itself . Hence the point Q of the ΔPQR overlap with the M.  

Now let us see the image attached with this. The Line LM and MN are extended further till Point P and R respectively.  

If LN = x and MN = y  

PM = 1.5x and MR = 1.5y  

as the scale of dilation is 1.5

Now let us see the the ratio of the sides of the two triangles.

Hence the ratio of the sides is same. There for the triangles are similar to each other.

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You need to write an essay that has at least 500 words you have written 285 words so far right and solve an inequality that Reec
andrezito [222]

Answer:

The minimum number of words left to write is 215

Step-by-step explanation:

Let

w -----> the number of words left to write

we know that

The number of words left to write plus the words written so far must be greater than or equal to 500 words

Remember that the word "at least" means "greater than or equal to"

so

w+285\geq 500                

Solve for w                        

Subtract 285 both sides        

w\geq 500-285\\w\geq 215

The minimum number of words left to write is 215

3 0
2 years ago
If the fastest you can safely drive is 65 mi/h, what is the longest time you can stop for dinner if you must travel 569 mi in 9.
stellarik [79]

Divide total miles by speed to get how long it will take to drive:

569 miles / 65 mi/h = 8.75 hours.

Now subtract the time it takes to drive from the total time you can travel:

9.5 hours - 8.75 hours = 0.75 hours.

You can stop for 0.75 hours.

4 0
2 years ago
Anumeha is mowing lawns for a summer job. For every mowing job, she charges an initial fee of $ 10 $10dollar sign, 10 plus a con
slavikrds [6]

Answer:

F(t) = 10 + 5(t)

Step-by-step explanation:

The complete question is as follows;

Anumeha is mowing lawns for a summer job. for every mowing job, she charges an initial fee of \$10$10dollar sign, 10 plus a constant fee for each hour of work. her fee for a 555-hour job, for instance, is \$35$35dollar sign, 35. let f(t)f(t)f, left parenthesis, t, right parenthesis denote anumeha's fee for a single job fff (measured in dollars) as a function of the number of hours ttt it took her to complete it. write the function's formula.

Solution

We are interested in writing the function F(t) formula for the fee charged by Anumeha per job.

Now, the key to writing this function is knowing exactly the constant fee she charges on the job.

We were told that she got $35 for a 5 hour job.

Thus, the constant amount charged is as follows;

Since it’s $10 as initial fee and the constant fee is per hour;

35 = 10 + 5(x)

where x is the constant fee per hour

35 = 10 + 5x

5x = 35-10

5x = 25

x = 25/5

x = $5

This mess that she charges a constant fee of $5 per hour

So we can write the equation now.

F(t) = 10 + 5(t)

where t represents the number of hours she spent on the job

6 0
2 years ago
In circle O, RT and SU are diameters. If m = m, what is m? 47° 52° 64° 87°
vlada-n [284]
From the given figure, it can be seen that 13x = 15x - 8 because they are vertical angles and thus are equal.

13x = 15x - 8
15x - 13x = 8
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x = 8/2 = 4

Thus, 15x - 8 = 15(4) - 8 = 60 - 8 = 52.

RT is a diameter, which means that mRT = 180

mRV + mVU + 52 = 180

mRV + mVU = 180 - 52 = 128

Now, given that mRV = mVU,

Thus, 2mVU = 128

Therefore, mVU = 128 / 2 = 64°
8 0
2 years ago
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adam invests $6,139 in an retirement account with a fixed annual interest rate compounded continuously. after 17 years the balan
Digiron [165]

2485.97 would be what he earned as an interest rate. The percentage would be6%

8 0
2 years ago
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