A printer can print 12 pages in 9 seconds. What is the closest estimate of the

Galactic Rotation Speed. We are located about 27,000 light-years from the galactic center and we orbit the center about once eve

Alexxandr [17]

Answer:

speed = 796142.197 km/hr

Step-by-step explanation:

solution

we consider here orbit around galactic center is circular so

circumference formula will be here

circumference C = 2πr ........1

here we know r = 27000

so

circumference C = 2 π × 27000

C = 169560 light year

so

we travel 169560 light year in 230000000 years

so distance will be

distance = $\frac{169560}{230000000}$

distance = 0.00073721 light year/year

and we know 1 year = 8760 hours

so 1 light year = 9.46027 × $10^{12}$ km

so

sped of moving is

speed = 0.00073721 × 9.46027 × $\frac{10^{12}}{8760}$ km/hr

speed = 796142.197 km/hr

5 0

2 years ago

6. Charlie can spend up to $8 on lunch. He wants to buy a tuna sandwich, a bottle of

PilotLPTM [1.2K]

Answer:

The maximum number of pounds of potato salad that Charlie can buy is 0.375

Step-by-step explanation:

see the attached figure to better understand the problem

Let

a ----> the cost of one tuna sandwich

b ----> the cost of a bottle of apple juice

c ----> the cost per pound of potato salad

x ----> pounds of potato salad

we have

$a=\$4.25$

$b=\$2.25$

$c=\$4.00/lb$

we know that

He wants to buy a tuna sandwich, a bottle of apple juice, and x pounds of potato salad and can spend up to $8

The inequality that represent this situation is

$a+b+cx \leq 8$

substitute the given values

$4.25+2.25+4.00x \leq 8$

Solve for x

Combine like terms

$6.50+4.00x \leq 8$

Subtract 6.50 both sides

$4.00x \leq 8-6.50$

$4.00x \leq 1.50$

Divide by 4 both sides

$x \leq 1.50/4.00$

$x \leq 0.375\ lbs$

therefore

The maximum number of pounds of potato salad that Charlie can buy is 0.375

3 0

2 years ago

Which equation represents a proportional relationship that has a constant of proportionality equal to –10? y = x minus 10 y = x/

kicyunya [14]

Answer:

y=-10x

Step-by-step explanation:

y=-10x

y/x=-10

6 0

2 years ago

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

5 0

2 years ago

Jacinta buys 4 pounds of turkey and 2 pounds of ham. She pays a total of $30, and the turkey costs $1.50 less per pound than the

marissa [1.9K]

Given

jacinta buys 4 pounds of turkey and 2 pounds of ham & pays a total of $30, turkey costs $1.50 less per pound than the ham.

find out the combined cost of 1 pound of turkey and 1 pound of ham

To proof

As given in the question

jacinta buys 4 pounds of turkey and 2 pounds of ham

total pay by jacinta = $30

let us assume that the price of the ham = x

as given in the question

turkey costs $1.50 less per pound than the ham

turkey costs becomes = x - 1.50

then the equation becomes

30 = 4 (x - 1.50) + 2x

30 = 4x + 2x - 6

36 = 6x

x = 6

thus

ham cost per pound = $6

turkey cost per pound = 6 - 1.50

= $ 4.5

Now find out

cost of 1 pound of turkey + 1 pound of ham = $ 6 + $ 4.5

= $ 10.5

Hence proved

5 0

2 years ago

Read 2 more answers