Question

PLZ FAST Solve for x in the equation 2 x squared minus 5 x + 1 = 3. x = five-halves plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction x = five-halves plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction x = five-fourths plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction x = five-fourths plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction

Answer 1

Answer:

$\frac{5}{4} +/-\frac{\sqrt{41} }{4}$

Step-by-step explanation:

We re-write the equation subtracting from both sides 3, so as to get a quadratic expression equal to zero and be able to use the quadratic formula to solve it:

$2x^2-5x+1=3\\2x^2-5x+1-3=0\\2x^2-5x-2=0$

Now we use the quadratic formula considering that $a=2, b=-5,\,and\,\,c=-2$

$x=\frac{-b+/-\sqrt{b^2-4\,a\,c} }{2\,a} \\x=\frac{-(-5)+/-\sqrt{(-5)^2-4\,(2)\,(-2)} }{2\,(2)} \\\\x=\frac{5+/-\sqrt{25+16} }{4} \\x=\frac{5+/-\sqrt{41} }{4} \\x=\frac{5}{4} +/-\frac{\sqrt{41} }{4}$

Answer 2

Answer:

Option D

Step-by-step explanation:

Took the test, its correct