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Salsk061 [2.6K]

2 years ago

5

at freds house, santa ate the same number of suger cookies and chocolate chip cookies. Twice the number of sugar cookies he ate

decreased by one equals the number of chocolate chip cookies he ate. How many sugar cookies (x) and chocolate chip cookies (y) did santa eat at fred's house

2 answers:

lawyer [7]2 years ago

6 0

751.2÷25= need help showing the way to get to the answer

Margaret [11]2 years ago

4 0

Answer:

<h2>Santa ate one sugar cookie and 1 chocolate chip cookies.</h2>

Step-by-step explanation:

We know that

<h3>Santa ate the same number of sugar cookies and chocolate chip cookies.</h3>

If $x$ represents sugar cookies, and $y$ represents chocolate chip cookies.

This part of the problem is expressed as

$x=y$

Because Santa ate the same of each type.

<h3>Twice the number of sugar cookies he ate decreased by one equals the number of chocolate chip cookies.</h3>

Now, this part of the problem is expressed

$2x-1=y$

Because twice of sugar cookies decreased by one is equals to chocolate chip cookies.

Replacing the first equation into the second one, we have

$2x-1=x\\2x-x=1\\x=1$

Now, replacing this value in the first equation, we have

$y=1$

Therefore, Santa ate one sugar cookie and 1 chocolate chip cookies.

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Answer:

g(x) exceed f(x) by $10$ when $x=5$

Step-by-step explanation:

step 1

Find the equation of function f(x)

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so

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The rate of change is equal to the slope

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step 2

Find the equation of function g(x)

Let

$A(0,-8),B(2,0)$

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step 3

Find the value of f(x) and g(x) for $x=5$

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$g(5)=4(5)-8=12$

Find the difference

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andreyandreev [35.5K]

Answer:

A bag of pop corn costs $8, and each Pretzel costs $4.25.

Step-by-step explanation:

Let $b$ be the price of popcorn, and $p$ the price of Pretzels. If the girl bought 2 bags of popcorn and 5 Pretzels and it cost her $37.25, we have the equation

$2b+5p=37.25$ <em>(this says that the cost of 2 popcorn bags plus 5 pretzels equals $37.25)</em> .

And, since Zoe bought 8 popcorn bags and 9 Pretzels with a total price of $102.25, we get the equation

$8b+9p=102.25$ <em> (this says that the cost of 8 popcorn bags plus 9 Pretzels equals $102.25).</em>

Thus, we have two equations

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and we solve them by first multiplying equation (1) by 4:

$4(2b+5p=37.25 )\rightarrow (8b+20p=149)$ ,

and then subtracting it from equation (2):

$\:\:\:\:\: 8b+9p=102.25\\-(8b+20p=149)\\\line(1,0){3 cm}\\-11p=-46.75\\\\\boxed{p=\$4.25}$

Now we put this value of $p$ into equation (1) and get:

$2b+5(4.25)=37.25$

and we solve for $b$ to get:

$2b=37.25-21.5$

$\boxed{ b=8}$

Therefore, a bag of popcorn costs $8, and each Pretzel costs $4.25.

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2 years ago