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slamgirl [31]
1 year ago
11

Function f is a linear function with an initial value of 17 and a rate of change of –3. Some values for the linear function g ar

e shown in the table below. By how much does g exceed f when x = 5?

Mathematics
1 answer:
tia_tia [17]1 year ago
3 0

Answer:

g(x) exceed f(x) by 10 when x=5

Step-by-step explanation:

step 1

Find the equation of function f(x)

we know that

The initial value is the y-intercept of the linear function (value of y when the value of x is equal to zero)

so

b=17

The rate of change is equal to the slope

so

m=-3

therefore

f(x)=-3x+17

step 2

Find the equation of function g(x)

Let

A(0,-8),B(2,0)

Find the slope

m=(0+8)/(2-0)=4

b=-8 ----> point A

therefore

g(x)=4x-8

step 3

Find the value of f(x) and g(x) for x=5

f(5)=-3(5)+17=2

g(5)=4(5)-8=12

Find the difference

g(5)-f(5)=12-2=10

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Answer:

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Step-by-step explanation:

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Answer:

S={(heart), (diamond), (club), (spade)}

Step-by-step explanation:

In probability, a set is a well-defined collection of objects, product of an independent successful operation.

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5 0
2 years ago
Solve rational inequality x²+x-6/x²-3x-4≤0?​
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Answer:

Step-by-step explanation:

x

2

+

x

−

6

=

(

x

+

3

)

(

x

−

2

)

x

2

−

3

x

−

4

=

(

x

−

4

)

(

x

+

1

)

Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:

x

=

−

3

,

−

1

,

2

,

4

Note that when

x

is large, the

x

2

terms will dominate the values of the numerator and denominator, making both positive.

Hence the sign of the value of the rational expression in each of the intervals

(

−

∞

,

−

3

)

,

(

−

3

,

−

1

)

,

(

−

1

,

2

)

,

(

2

,

4

)

and

(

4

,

∞

)

follows the pattern

+

−

+

−

+

. Hence the intervals

(

−

3

,

−

1

)

and

(

2

,

4

)

are both part of the solution set.

When

x

=

−

1

or

x

=

4

, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).

When

x

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−

3

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x

=

2

, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.

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x

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graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}

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Add C to both sides:

R-P=C

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